python中编写一个聪明版的尼姆游戏程序

在Python中编写一个聪明版的“石头、剪刀、布”（也称为“尼姆”游戏）程序，我们可以创建一个玩家和电脑对战的游戏。首先，我们需要定义一些规则，比如每次玩家和电脑都选择一种手势（石头、剪刀或布），然后判断胜负。以下是一个简单的示例：

import random

def play_game():
    options = ['rock', 'paper', 'scissors']
    player_score = 0
    computer_score = 0

    while True:
        print("Player's turn:")
        player_choice = input("Choose rock, paper, or scissors: ").lower()

        if player_choice not in options:
            print("Invalid choice! Try again.")
            continue
        
        computer_choice = random.choice(options)
        print(f"Computer chose {computer_choice}.")

        if player_choice == computer_choice:
            print("It's a tie!")
        elif (player_choice == 'rock' and computer_choice == 'scissors') or \
             (player_choice == 'paper' and computer_choice == 'rock') or \
             (player_choice == 'scissors' and computer_choice == 'paper'):
            print("Player wins!")
            player_score += 1
        else:
            print("Computer wins!")
            computer_score += 1

        if player_score == 3 or computer_score == 3:
            break

    if player_score > computer_score:
        print("Congratulations! Player wins the game!")
    else:
        print("Game over! Computer wins with a score of", computer_score.)

play_game()

在这个游戏中，玩家输入他们的选择，电脑随机生成一个选择。如果两者相同，则平局；如果按照“石头赢剪刀，剪刀赢布，布赢石头”的规则，判定胜者并更新分数。当一方累积达到3分时，游戏结束。