约瑟夫问题。N个人围成一圈，第一个人开始从1报数，报到M的将被杀掉，下一个人接着从1开始报数，如此反复，最后剩一个。求最后的胜利者。 要求：循环链表实现 (java类)

以下是使用循环链表实现约瑟夫问题的Java类的示例代码：

public class JosephusProblem {
    static class Node {
        int data;
        Node next;

        Node(int data) {
            this.data = data;
            this.next = null;
        }
    }

    static int getJosephusPosition(int n, int m) {
        Node head = new Node(1);
        Node prev = head;
        for (int i = 2; i <= n; i++) {
            prev.next = new Node(i);
            prev = prev.next;
        }
        prev.next = head;

        Node curr = head;
        while (curr.next != curr) {
            for (int i = 1; i < m - 1; i++) {
                curr = curr.next;
            }
            curr.next = curr.next.next;
            curr = curr.next;
        }

        return curr.data;
    }

    public static void main(String[] args) {
        int n = 5; // 总人数
        int m = 2; // 报数到m的人将被杀掉
        int winner = getJosephusPosition(n, m);
        System.out.println("The winner is: " + winner);
    }
}