长度分别为m和n的升序链表,若合并为一个长度
时间: 2023-02-16 18:48:19 浏览: 88
你好! 我可以用中文回答你的问题。
你问的是两个长度分别为m和n的升序链表如何合并为一个长度。这是一个比较经典的问题,我可以给你一个解决方案。
首先,我们定义一个新的链表用于存储合并后的结果。然后,我们比较两个链表的头节点(head node),将较小的节点插入新链表中。然后,我们继续比较剩余节点,直到两个链表都遍历完毕。
下面是一个算法的伪代码:
```
def merge_sorted_lists(head1, head2):
# define a new linked list to store the result
merged_list_head = None
merged_list_tail = None
# until both linked lists are empty
while head1 is not None or head2 is not None:
# if both lists are not empty, compare the head nodes
if head1 is not None and head2 is not None:
# insert the smaller node into the merged list
if head1.val <= head2.val:
new_node = head1
head1 = head1.next
else:
new_node = head2
head2 = head2.next
# if only one of the lists is empty, insert the remaining nodes from the non-empty list
elif head1 is not None:
new_node = head1
head1 = head1.next
elif head2 is not None:
new_node = head2
head2 = head2.next
# if this is the first node being inserted, set it as the head of the merged list
if merged_list_head is None:
merged_list_head = new_node
merged_list_tail = new_node
# otherwise, insert it after the tail of the merged list
else:
merged_list_tail.next = new_node
merged_list_tail = new_node
# return the head of the merged list
return merged_list_head
```
这个算法的时间复杂度是O(m+n),因为我们需要遍历每个节点