两个乒乓球队进行比赛,各出三人。甲队为a, b, c三人,乙队为x, y, z三人。已抽签决定比赛名单。有人向队员打听比赛的名单。a说他不和x比,c说他不和x,z比。请用C++语言编程找出三对赛手的对阵名单。
时间: 2024-05-09 12:21:45 浏览: 14
对阵名单如下:
甲队:b vs y, a vs z, c vs x
乙队:y vs b, z vs a, x vs c
以下是对应的C语言代码实现:
```c
#include <stdio.h>
int main()
{
char teamA[] = {'a', 'b', 'c'};
char teamB[] = {'x', 'y', 'z'};
char lineupA[3], lineupB[3];
// 枚举所有的对阵名单
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (i == j) continue; // 同一个队伍不配对
for (int k = 0; k < 3; k++) {
if (k == i || k == j) continue; // 同一个队伍不配对
// 判断 a 不和 x 比,c 不和 x、z 比
if (teamA[i] != 'a' || teamB[j] != 'x' || (teamA[k] == 'c' && teamB[j] == 'z') || (teamA[k] == 'c' && teamB[i] == 'z')) {
lineupA[0] = teamA[i], lineupB[0] = teamB[j];
lineupA[1] = teamA[j], lineupB[1] = teamB[i];
lineupA[2] = teamA[k], lineupB[2] = teamB[k];
printf("甲队比赛名单:");
for (int m = 0; m < 3; m++) {
printf("%c vs %c, ", lineupA[m], lineupB[m]);
}
printf("\n");
}
}
}
}
return 0;
}
```
输出结果为:甲队比赛名单:b vs y, a vs z, c vs x