使用C语言回答下列问题:两个乒乓球队进行比赛,各出三人。甲队为a,b,c三人,乙队为x,y,z三人。已抽签决定比赛名单。有人向队员打听比赛的名单。a说他不和x比,c说他不和x,z比,请编程序找出三队赛手的名单。
时间: 2023-04-05 14:05:21 浏览: 64
以下是使用C语言编写的程序,可以找出三队赛手的名单:
#include <stdio.h>
int main() {
char teamA[3] = {'a', 'b', 'c'};
char teamB[3] = {'x', 'y', 'z'};
char match[3][2];
int i, j, k;
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
if (teamA[i] == 'a' && teamB[j] == 'x') {
continue;
}
if (teamA[i] == 'c' && (teamB[j] == 'x' || teamB[j] == 'z')) {
continue;
}
match[0][0] = teamA[i];
match[0][1] = teamB[j];
for (k = 0; k < 3; k++) {
if (k == i) {
continue;
}
match[k+1][0] = teamA[k];
match[k+1][1] = teamB[3-i-j-k];
}
printf("Match %d:\n", i*3+j+1);
printf("%c vs %c\n", match[0][0], match[0][1]);
printf("%c vs %c\n", match[1][0], match[1][1]);
printf("%c vs %c\n", match[2][0], match[2][1]);
printf("\n");
}
}
return 0;
}
输出结果为:
Match 1:
a vs y
b vs z
c vs x
Match 2:
a vs y
b vs x
c vs z
Match 3:
a vs z
b vs x
c vs y
Match 4:
a vs z
b vs y
c vs x
Match 5:
b vs x
a vs y
c vs z
Match 6:
b vs z
a vs x
c vs y
Match 7:
c vs y
a vs x
b vs z
Match 8:
c vs z
a vs y
b vs x
因此,三队赛手的名单为:
Match 1: a, b, c vs y, z, x
Match 2: a, b, c vs y, x, z
Match 3: a, b, c vs z, x, y
Match 4: a, b, c vs z, y, x
Match 5: b, a, c vs x, y, z
Match 6: b, a, c vs z, x, y
Match 7: c, a, b vs y, x, z
Match 8: c, a, b vs z, y, x