解释s.sort(key=lambda x:sum(int(i) for i in str(x)))

这段代码使用了Python的sort()函数，对一个列表s进行排序。其中，key参数是一个函数，它指定了排序的规则。lambda表达式是一个匿名函数，它的参数是x，函数体为对x进行求和的操作。具体来说，对于x中的每个元素i，将其转换为整数后再求和。这个函数的作用是将列表中的每个元素按照其各位数字之和进行排序。

相关问题

s.sort(key=lambda x:sum(int(i) for i in str(x)))什么意思

这行代码是对列表s进行排序，排序依据是每个元素的各个数字的和。lambda函数作为key参数传入sort()函数中，用于计算每个元素的各个数字的和。具体地，lambda函数将每个元素x转换为字符串，然后遍历字符串中的每个字符i，将其转换为整型并求和，返回结果作为每个元素的排序依据。排序结果是按照元素的各个数字的和从小到大排列的。

n=int(input()) m=int(input()) s=list(range(1,n+1)) s.sort(key=lambda x:sum(int(i) for i in str(x))) print(s[m-1])

This code takes two integer inputs n and m, creates a list s of numbers from 1 to n-1, sorts the list based on the sum of digits of each number converted to an integer, and finally prints the m-th element of the sorted list.

However, there is a syntax error in the code. The line "s=list(range(1,n 1))" should have a comma between n and 1: "s=list(range(1, n+1))".

Also, it would be helpful to add comments to explain what each line of the code does. Here's the corrected code with comments:

# take input for n and m
n = int(input())
m = int(input())

# create a list of numbers from 1 to n-1
s = list(range(1, n+1))

# sort the list based on the sum of digits of each number
s.sort(key=lambda x: sum(int(i) for i in str(x)))

# print the m-th element of the sorted list
print(s[m-1])