c++棋牌类小游戏源代码

抱歉，我无法提供完整的源代码，但我可以给你一个简单的示例来实现一个基于C++的棋牌类小游戏。这里是一个井字棋（Tic Tac Toe）的示例代码：

#include <iostream>
#include <vector>

using namespace std;

// 井字棋游戏类
class TicTacToe {
public:
    TicTacToe() {
        board = vector<vector<char>>(3, vector<char>(3, ' '));
        currentPlayer = 'X';
    }

    void playGame() {
        int row, col;
        bool gameOver = false;

        while (!gameOver) {
            displayBoard();
            cout << "Player " << currentPlayer << ", enter your move (row and column): ";
            cin >> row >> col;

            if (isValidMove(row, col)) {
                makeMove(row, col);

                if (isWinner()) {
                    displayBoard();
                    cout << "Player " << currentPlayer << " wins!" << endl;
                    gameOver = true;
                } else if (isBoardFull()) {
                    displayBoard();
                    cout << "It's a draw!" << endl;
                    gameOver = true;
                } else {
                    switchPlayer();
                }
            } else {
                cout << "Invalid move! Try again." << endl;
            }
        }
    }

private:
    vector<vector<char>> board;
    char currentPlayer;

    void displayBoard() {
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                cout << board[i][j] << " ";
            }
            cout << endl;
        }
    }

    bool isValidMove(int row, int col) {
        if (row >= 0 && row < 3 && col >= 0 && col < 3 && board[row][col] == ' ') {
            return true;
        }
        return false;
    }

    void makeMove(int row, int col) {
        board[row][col] = currentPlayer;
    }

    void switchPlayer() {
        currentPlayer = (currentPlayer == 'X') ? 'O' : 'X';
    }

    bool isWinner() {
        // 检查行
        for (int i = 0; i < 3; i++) {
            if (board[i][0] == currentPlayer && board[i][1] == currentPlayer && board[i][2] == currentPlayer) {
                return true;
            }
        }

        // 检查列
        for (int i = 0; i < 3; i++) {
            if (board[0][i] == currentPlayer && board[1][i] == currentPlayer && board[2][i] == currentPlayer) {
                return true;
            }
        }

        // 检查对角线
        if (board[0][0] == currentPlayer && board[1][1] == currentPlayer && board[2][2] == currentPlayer) {
            return true;
        }
        if (board[0][2] == currentPlayer && board[1][1] == currentPlayer && board[2][0] == currentPlayer) {
            return true;
        }

        return false;
    }

    bool isBoardFull() {
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                if (board[i][j] == ' ') {
                    return false;
                }
            }
        }
        return true;
    }
};

int main() {
    TicTacToe game;
    game.playGame();

    return 0;
}

这是一个简单的井字棋小游戏的源代码。你可以根据需要进行修改和扩展。希望对你有所帮助！