Return the number of times that the string "hi" appears anywhere in the given string

Sure! Here's the Python code to count the number of times the string "hi" appears in a given string:

def count_hi(string):
    return string.count("hi")

You can call this function with a string argument to get the count of "hi" in that string. For example:

>>> count_hi("hi there hi")
2
>>> count_hi("hiking on a hill")
0
>>> count_hi("hitherehitherehi")
3

相关问题

Return the number of times that the string "hi" appears anywhere in the given string.

Sure! Here's a Python code snippet that does what you're asking for:

def count_hi(string):
    return string.count('hi')

You can call this function with a string as its argument and it will return the number of times that the substring "hi" appears anywhere in the string. For example:

>>> count_hi('hi there hi hi')
3
>>> count_hi('oh hi mark')
1
>>> count_hi('nope')
0

Let me know if you have any other questions!

Return the number of times that the string "code" appears anywhere in the given string, except we'll accept any letter for the 'd', so "cope" and "cooe" count.

这个问题可以通过编写一个函数来解决。函数的输入是一个字符串，输出是字符串中出现 "code" 的次数。

以下是一个可能的解决方案：

def count_code(str):
  count = 0
  for i in range(len(str)-3):
    if str[i:i+2] == 'co' and str[i+3] == 'e':
      count += 1
  return count

这个函数使用一个循环来遍历字符串中的所有可能的子字符串。如果子字符串以 "co" 开头，以 "e" 结尾，并且第四个字符可以是任何字符，那么就说明这个子字符串包含了一个 "code"。每当发现这样的子字符串时，计数器就加一。最后返回计数器的值即可。

请注意，这个函数对于大小写是敏感的，因此它只能匹配 "code"、"CoDe" 等完全相同的形式，而不能匹配 "CoDe"、"CODE" 等形式。如果需要不区分大小写的匹配，可以将输入字符串和子字符串都转换为小写或大写形式。