设计一个代码，输入一个一元二次方程的系数abc,若a为0，求x的值，若a不为零，delta大于等于零时求实实数解，若delta小于零给出无实数解的信息

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    double a, b, c;
    cin >> a >> b >> c;
    if (a == 0) {
        if (b == 0) {
            if (c == 0) {
                cout << "方程有无数解" << endl;
            } else {
                cout << "方程无解" << endl;
            }
        } else {
            cout << "方程的解为：" << -c / b << endl;
        }
    } else {
        double delta = b * b - 4 * a * c;
        if (delta >= 0) {
            double x1 = (-b + sqrt(delta)) / (2 * a);
            double x2 = (-b - sqrt(delta)) / (2 * a);
            cout << "方程的实数解为：" << x1 << "和" << x2 << endl;
        } else {
            cout << "方程无实数解" << endl;
        }
    }
    return 0;
}