用Python语言编写输出结果为如下的代码：请输入字符串(以#号结束):i+i*i# 待分析 产生式 剩余 i E一>TE1 +i*i# i T->FT1 +i*i# i F->i +i*i# i+ T1->E i丰i# i+ E1->+TE1 i本i# i+i T->FT1 *i# i+i F->i *i# i+i* T1->FT1 i# i+i*i F->i # i+i*i# T1->E i+i*i#E1->RIGHT, AGAIN! 语法分析完毕!退出? y or n

以下是Python代码：

stack = ['#', 'E']
input_str = input("请输入字符串(以#号结束):")
i = 0

while True:
    if stack[-1] == '#' and input_str[i] == '#':
        print("RIGHT, AGAIN! 语法分析完毕!")
        break
    elif stack[-1] == input_str[i]:
        stack.pop()
        i += 1
    else:
        if stack[-1] == 'E':
            if input_str[i] == 'i':
                stack.pop()
                stack.append('T')
                stack.append('E1')
            else:
                print("WRONG! 退出语法分析!")
                break
        elif stack[-1] == 'E1':
            if input_str[i] == '+':
                stack.pop()
                stack.append('T')
                stack.append('E1')
                stack.append('+')
            else:
                stack.pop()
        elif stack[-1] == 'T':
            if input_str[i] == 'i':
                stack.pop()
                stack.append('F')
                stack.append('T1')
            else:
                print("WRONG! 退出语法分析!")
                break
        elif stack[-1] == 'T1':
            if input_str[i] == '*':
                stack.pop()
                stack.append('F')
                stack.append('T1')
                stack.append('*')
            else:
                stack.pop()
        elif stack[-1] == 'F':
            if input_str[i] == 'i':
                stack.pop()
                stack.append('i')
            else:
                print("WRONG! 退出语法分析!")
                break
        else:
            print("WRONG! 退出语法分析!")
            break

answer = input("退出? y or n")
if answer == 'y':
    exit()