python调用webservice接口基于用户密码授权调用QueryUserParams 类
时间: 2024-06-09 08:12:18 浏览: 12
好的,可以尝试以下代码:
```python
import requests
import xml.etree.ElementTree as ET
# 输入用户名和密码
username = "your_username"
password = "your_password"
# 构造SOAP消息
soap_message = '''
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:typ="http://types.webservice.namespace">
<soapenv:Header/>
<soapenv:Body>
<typ:QueryUserParams>
<typ:userId>your_userId</typ:userId>
</typ:QueryUserParams>
</soapenv:Body>
</soapenv:Envelope>
'''
# 发送SOAP请求
response = requests.post(url="your_web_service_url",
data=soap_message,
headers={'Content-Type': 'text/xml;charset=UTF-8'})
# 解析SOAP响应
tree = ET.fromstring(response.content)
namespaces = {'ns': 'http://types.webservice.namespace'}
result = tree.find('.//ns:QueryUserParamsResult', namespaces=namespaces)
# 输出结果
print(result.text)
```
其中,需要将`your_username`和`your_password`替换为实际的用户名和密码,`your_userId`替换为要查询的用户ID,`your_web_service_url`替换为实际的webservice接口地址。另外,需要安装`requests`和`xml`模块。