String s1=new String("hello")+new String("world");输出s1的结果是什么

这段代码是错误的，因为在初始化字符串时只能使用一个字符串字面量或一个字符串变量。如果您想将两个字符串 "hello" 和 "world" 连接在一起并赋值给 s1 变量，可以使用加号运算符，如下所示：

String s1 = "hello" + "world";

这将创建一个新的字符串 "helloworld" 并将其分配给 s1 变量。

相关问题

public class stringT { ​public static void main(String[] args) { ​​String s1 = "Hello"; String s2 = "World"System.out.println(s1.equals(s2))

您的代码有语法错误，缺少分号和右括号。正确的代码如下：

public class stringT { 
    public static void main(String[] args) { 
        String s1 = "Hello"; 
        String s2 = "World";
        System.out.println(s1.equals(s2));
    }
}

这段代码会输出 `false`，因为 `s1` 和 `s2` 的值不相等。如果您想要比较两个字符串是否相等，可以使用 `equals()` 方法。

s1=set('hello'),s2=set('world'), s1&s2的结果c是(),

intersection(s2)

The output of this code would be {'o', 'l'}, because these are the letters that are common to both 'hello' and 'world'.

Here's how it works:

- `set('hello')` creates a set containing the unique characters in the string 'hello', which are 'h', 'e', 'l', and 'o'.
- `set('world')` creates a set containing the unique characters in the string 'world', which are 'w', 'o', 'r', 'l', and 'd'.
- `s1.intersection(s2)` returns a new set containing the elements that are in both `s1` and `s2`. In this case, that means the letters 'o' and 'l', since those are the only letters that appear in both 'hello' and 'world'.