_destroy_aux
时间: 2023-10-01 13:05:31 浏览: 44
_destroy_aux是一个函数模板,根据元素的数值型别(value type)是否有自定义的析构函数来选择不同的操作。如果元素的数值型别有自定义的析构函数(即non-trivial destructor),则会遍历迭代器指向的元素,并调用对象的析构函数进行析构。如果元素的数值型别没有自定义的析构函数(即trivial destructor),则不会进行任何操作。
相关问题
class_destroy
class_destroy 是Linux内核中用于销毁一个设备类 (struct class) 的函数。它的原型如下:
void class_destroy(struct class *cls);
其中,cls 是一个指向设备类的指针,表示要销毁的设备类。
在调用 class_destroy 函数之前,需要确保已经将该设备类从系统中移除,并且没有设备实例或驱动程序使用该设备类。否则,会导致未定义的行为或内存泄漏。
class_destroy 函数会释放设备类所占用的资源,并将其从系统中删除。这包括释放设备类的名字和属性文件,以及解除与其他系统资源的关联。
需要注意的是,class_destroy 函数只能销毁由 class_create 函数创建的设备类,而不能销毁由其他方式创建的设备类。
sem_destroy
sem_destroy is a function in the C programming language that is used to destroy a named or unnamed semaphore.
Syntax:
```
#include <semaphore.h>
int sem_destroy(sem_t *sem);
```
Parameters:
- `sem`: Pointer to the semaphore that needs to be destroyed.
Return Value:
The sem_destroy function returns 0 on success, and -1 on failure.
Description:
The sem_destroy function is used to destroy a semaphore that was previously created using the sem_init or sem_open function. Once a semaphore has been destroyed, all threads waiting on it will be unblocked and any resources associated with it will be released.
Note:
- Before calling sem_destroy, all threads waiting on the semaphore must be unblocked.
- Once a semaphore has been destroyed, it cannot be used again until it is re-initialized using sem_init or sem_open.
Example:
```
#include <stdio.h>
#include <semaphore.h>
#include <pthread.h>
sem_t semaphore;
void* myThread(void* arg){
sem_wait(&semaphore);
printf("Thread is waiting on semaphore\n");
sem_post(&semaphore);
printf("Thread has finished waiting on semaphore\n");
return NULL;
}
int main(){
sem_init(&semaphore, 0, 1);
pthread_t threadID;
pthread_create(&threadID, NULL, &myThread, NULL);
pthread_join(threadID, NULL);
sem_destroy(&semaphore);
printf("Semaphore has been destroyed\n");
return 0;
}
```
In the above example, the sem_destroy function is called to destroy the semaphore after the thread has finished waiting on it.