输入N个数到数组中,输出所有大于N个数平均值的数。用java

在Java中，你可以创建一个方法来接收用户输入的N个数，并计算它们的平均值，然后找出所有大于平均值的数。以下是一个基本的示例代码：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("请输入数字的数量(N): ");
        int n = scanner.nextInt(); // 获取数字的数量
        double[] numbers = new double[n];

        System.out.println("请输入" + n + "个数：");
        for (int i = 0; i < n; i++) {
            numbers[i] = scanner.nextDouble(); // 存储用户输入的每个数
        }

        scanner.close();

        // 计算平均值
        double average = calculateAverage(numbers);

        // 找出大于平均值的数并打印
        findAndPrintNumbersGreaterThanAverage(numbers, average);
    }

    private static double calculateAverage(double[] numbers) {
        double sum = 0;
        for (double num : numbers) {
            sum += num;
        }
        return sum / numbers.length;
    }

    private static void findAndPrintNumbersGreaterThanAverage(double[] numbers, double average) {
        System.out.println("大于平均值的数有：");
        for (int i = 0; i < numbers.length; i++) {
            if (numbers[i] > average) {
                System.out.print(numbers[i] + " ");
            }
        }
    }
}