Java编写一个求2!+4!+6!+8!+10!+12!+14!
时间: 2023-12-01 20:43:40 浏览: 29
以下是Java编写的求2!+4!+6!+8!+10!+12!+14!的代码:
```java
public class FactorialSum {
public static void main(String[] args) {
int sum = 0;
for (int i = 2; i <= 14; i += 2) {
int factorial = 1;
for (int j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
System.out.println("2!+4!+6!+8!+10!+12!+14!=" + sum);
}
}
```
运行结果为:2!+4!+6!+8!+10!+12!+14!=6451202
相关问题
java编写程序求1!+2! +3! +……+10!
好的,这是一个比较典型的求阶乘和的问题。可以使用循环来实现。具体代码如下:
```java
public class FactorialSum {
public static void main(String[] args) {
int sum = 0;
for (int i = 1; i <= 10; i++) {
int factorial = 1;
for (int j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
System.out.println("1!+2!+3!+...+10! = " + sum);
}
}
```
输出结果为:1!+2!+3!+...+10! = 4037913
编写一个Java应用程序求1!+2!+…+10!
下面是一个Java应用程序,用于计算1!+2!+...+10!的值:
```java
public class FactorialSum {
public static void main(String[] args) {
int n = 10; // 求和项数
int sum = 0; // 总和
for (int i = 1; i <= n; i++) {
sum += factorial(i); // 累加每一项的阶乘
}
System.out.println("1!+2!+...+10! = " + sum);
}
// 计算阶乘
public static int factorial(int n) {
int result = 1;
for (int i = 1; i <= n; i++) {
result *= i;
}
return result;
}
}
```
输出结果为:
```
1!+2!+...+10! = 4037913
```