import sys def solve_method(m, n, jobs): jobs = sorted(jobs) if n <= m: print(max(jobs)) return res = jobs[:m] for i in range(m, n): min_val = min(res) min_idx = res.index(min_val) res[min_idx] += jobs[i] print(max(res)) if __name__ == '__main__': m, n = map(int, input().split()) jobs = list(map(int, input().split())) solve_method(m, n, jobs) 帮我改写一下
时间: 2024-04-17 13:24:50 浏览: 30
您好!根据您提供的代码,我已经您进行了改写。请查看以下代码:
```python
import sys
def solve_method(m, n, jobs):
jobs = sorted(jobs)
if n <= m:
return max(jobs)
res = jobs[:m]
for i in range(m, n):
min_val = min(res)
min_idx = res.index(min_val)
res[min_idx] += jobs[i]
return max(res)
if __name__ == '__main__':
m, n = map(int, input().split())
jobs = list(map(int, input().split()))
print(solve_method(m, n, jobs))
```
改写后的代码与原始代码功能相同,只是将原来的打印语句修改为返回最大值。这样,您可以在调用`solve_method()`函数时获取最大值,并根据需要进行处理。
相关问题
python代码加注释,代码如下def solve_method(n): step1 = 1 step2 = 1 step3 = 2 step4 = 1 if n == 1 or n == 2 else 2 for i in range(4, n + 1): step4 = step3 + step1 step1 = step2 step2 = step3 step3 = step4 print(step4) n = int(input().strip()) solve_method(n)
当然可以,以下是带注释的代码:
```python
def solve_method(n): # 定义函数 solve_method,接收参数 n
step1 = 1 # 初始化第一步和第二步的步数
step2 = 1
step3 = 2 # 初始化第三步的步数
step4 = 1 if n == 1 or n == 2 else 2 # 初始化第四步的步数,如果 n 等于 1 或 2,步数为 1,否则为 2
for i in range(4, n + 1): # 循环从 4 到 n
step4 = step3 + step1 # 计算第四步的步数
step1 = step2 # 更新第一步的步数
step2 = step3 # 更新第二步的步数
step3 = step4 # 更新第三步的步数
print(step4) # 输出第四步的步数
n = int(input().strip()) # 获取输入的 n 值
solve_method(n) # 调用函数 solve_method,计算步数并输出结果
```
希望这样能够帮助您理解代码的功能和实现。
import collections def solve_method(n: int) -> None: asc = True list_ = collections.deque() x = 1 for i in range(1, n + 1): arr = [0] * i if asc: for j in range(i): arr[j] = x x += 1 else: for j in range(i - 1, -1, -1): arr[j] = x x += 1 list_.appendleft(arr) asc = not asc res = [] head = "" for ints in list_: content = head for j in range(len(ints)): num = ints[j] content += str(num) content += "*" * (4 - len(str(num))) if j != len(ints) - 1: content += " " res.append(content) head += " " for s in reversed(res): print(s) if __name__ == "__main__": n = int(input()) solve_method(n) 改写以上代码,python
import collections
def solve_method(n):
asc = True
list_ = collections.deque()
x = 1
for i in range(1, n + 1):
arr = [0] * i
if asc:
for j in range(i):
arr[j] = x
x += 1
else:
for j in range(i - 1, -1, -1):
arr[j] = x
x += 1
list_.appendleft(arr)
asc = not asc
res = []
head = ""
for ints in list_:
content = head
for j in range(len(ints)):
num = ints[j]
content += str(num)
content += "*" * (4 - len(str(num)))
if j != len(ints) - 1:
content += " "
res.append(content)
head += " "
for s in reversed(res):
print(s)
if __name__ == "__main__":
n = int(input())
solve_method(n)
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