import random def solve(): print() n=int(input(" n: ")) a=random.sample(range(0,100),n) print(" 整数序列:",a) res=Max(a,n-1) print(" 最大整数:%d" %(res)) print() def Max(a,i): #主程序 solve()
时间: 2024-01-19 18:01:58 浏览: 29
这段代码的主要功能是生成一个长度为 n 的随机整数序列,然后找出其中的最大值。其中 `Max` 函数使用了分治法,将序列不断拆分成两部分,分别求解左半部分的最大值和右半部分的最大值,再将两部分的最大值比较,取较大值作为整个序列的最大值。
以下是完整的代码:
```python
import random
def solve():
print()
n = int(input(" n: "))
a = random.sample(range(0, 100), n)
print(" 整数序列:", a)
res = Max(a, n - 1)
print(" 最大整数:%d" % (res))
print()
def Max(a, i):
if i == 0:
return a[0]
else:
max1 = Max(a, i - 1)
max2 = Max(a[i:], len(a) - i - 1)
return max1 if max1 > max2 else max2
# 主程序
solve()
```
你可以运行这段代码,输入一个整数 n,程序会生成一个长度为 n 的随机整数序列,然后输出序列中的最大值。
相关问题
import collections def solve_method(n: int) -> None: asc = True list_ = collections.deque() x = 1 for i in range(1, n + 1): arr = [0] * i if asc: for j in range(i): arr[j] = x x += 1 else: for j in range(i - 1, -1, -1): arr[j] = x x += 1 list_.appendleft(arr) asc = not asc res = [] head = "" for ints in list_: content = head for j in range(len(ints)): num = ints[j] content += str(num) content += "*" * (4 - len(str(num))) if j != len(ints) - 1: content += " " res.append(content) head += " " for s in reversed(res): print(s) if __name__ == "__main__": n = int(input()) solve_method(n) 改写以上代码,python
import collections
def solve_method(n):
asc = True
list_ = collections.deque()
x = 1
for i in range(1, n + 1):
arr = [0] * i
if asc:
for j in range(i):
arr[j] = x
x += 1
else:
for j in range(i - 1, -1, -1):
arr[j] = x
x += 1
list_.appendleft(arr)
asc = not asc
res = []
head = ""
for ints in list_:
content = head
for j in range(len(ints)):
num = ints[j]
content += str(num)
content += "*" * (4 - len(str(num)))
if j != len(ints) - 1:
content += " "
res.append(content)
head += " "
for s in reversed(res):
print(s)
if __name__ == "__main__":
n = int(input())
solve_method(n)
import random class Solution: def solve(self): s="abcdefghijklmnopqrst\ uvwxyzABCDEFGHIJKLMNOPQRST\ UVWXYZ1234567890!@#$%^&*" li = [] for i in range(0, 10): li2 = [] for i in range(0, 10): if i == 0: x = random.randint(0, 69) while x in li: x = random.randint(0, 69) li.append(x) else: x = random.randint(0, 69) li2.append(s[x]) a = "".join(li2) with open("step3/output.txt", "w") as f: f.write(a + '\n') 文件里如何有十行密码
这段代码实现了生成随机密码的功能。具体来说,它将包含各种字符的字符串 s 定义为密码字符集,然后生成 10 个密码,每个密码包含 10 个随机选择的密码字符。生成每个密码时,它会确保每个字符都是唯一的,以避免密码中有重复字符。
如果你想让这段代码生成十行密码并将它们写入文件,可以将代码修改为:
```
import random
class Solution:
def solve(self):
s="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!@#$%^&*"
with open("step3/output.txt", "w") as f:
for i in range(10):
li = []
for j in range(10):
x = random.randint(0, 69)
while x in li:
x = random.randint(0, 69)
li.append(x)
f.write(s[x])
f.write('\n')
```
这样会生成十个长度为 10 的密码,并将它们写入名为 "output.txt" 的文件中,每个密码占一行。