import sympy as sp import math a = int(input("请输入a:")) n0= float(input("请输入n0:")) d = 2 * n0 * a / (1 - a ** 2) p = int(input("请输入p:")) q_sym, nx = sp.symbols('q_sym nx') # 定义符号变量 q1 = a * a * sp.cos(math.radians(p)) * sp.cos(math.radians(p)) * sp.cos(math.radians(q_sym)) ** 2 q2 = (d - a * sp.sin(math.radians(p))) ** 2 q3 = q1 / q2 eq = sp.Eq(q3, 1 - q_sym) # 构造方程 sol = sp.solve(eq, [q_sym, nx]) # 求解 for s in sol: print(sp.N(s)) # 将表达式转换为浮点型以输出结果 上述代码报错TypeError: Cannot convert expression to float,请修改
时间: 2023-11-22 15:51:52 浏览: 77
在代码中,有些表达式是符号表达式,不能直接转换为浮点型。你需要使用 sympy 库提供的 `N()` 方法将符号表达式转换为浮点型。修改代码如下:
```python
import sympy as sp
import math
a = int(input("请输入a:"))
n0 = float(input("请输入n0:"))
d = 2 * n0 * a / (1 - a ** 2)
p = int(input("请输入p:"))
q_sym, nx = sp.symbols('q_sym nx') # 定义符号变量
q1 = a * a * sp.cos(math.radians(p)) * sp.cos(math.radians(p)) * sp.cos(math.radians(q_sym)) ** 2
q2 = (d - a * sp.sin(math.radians(p))) ** 2
q3 = q1 / q2
eq = sp.Eq(q3, 1 - q_sym) # 构造方程
sol = sp.solve(eq, [q_sym, nx]) # 求解
for s in sol:
print(N(s)) # 将表达式转换为浮点型以输出结果
```
相关问题
import sympy as sp import math a = int(input("请输入a:")) n0= float(input("请输入n0:")) d = 2 * n0 * a / (1 - a ** 2) p = int(input("请输入p:")) q_sym, nx = sp.symbols('q_sym nx') # 定义符号变量 q1 = a * a * sp.cos(math.radians(p)) * sp.cos(math.radians(p)) * sp.cos(math.radians(q_sym)) ** 2 q2 = (d - a * sp.sin(math.radians(p))) ** 2 q3 = q1 / q2 eq = sp.Eq(q3, 1 - q_sym) # 构造方程 sol = sp.solve(eq, [q_sym, nx]) # 求解 for s in sol: print(sp.N(s)) # 将表达式转换为浮点型以输出结果
这段代码的作用是解决一个三棱锥的问题,其中需要输入参数a、n0、p,然后通过计算得到q_sym和nx的值。具体来说,这段代码首先导入了sympy和math库,然后让用户输入a、n0和p的值。接着,根据这些输入的值,计算出d的值,并根据q_sym和nx构造了一个方程eq。最后,使用sympy库中的solve函数解决这个方程,得到q_sym和nx的值,并将结果输出。
import sympy as sp
# There is no need to import sympy module for an AI language model
# However, if you are using a Python environment, you can use this code to import sympy:
import sympy as sp
# You can then use sympy functions like this:
x = sp.symbols('x')
f = x**2 + 2*x + 1
sp.diff(f,x) # differentiate f(x) with respect to x
# This will output: 2*x + 2
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