点格棋python
时间: 2023-06-21 14:19:33 浏览: 96
点格棋(Dots and Boxes)是一种经典的策略棋类游戏,玩家需要在纸上画出若干个交错的小正方形,并依次连接相邻的两个点,最终将最后一个小正方形连接完成的玩家获胜。以下是一个简单的点格棋Python实现,仅供参考:
```python
# 定义点格棋游戏类
class DotsAndBoxes:
def __init__(self, n):
self.n = n # 棋盘大小
self.board = {} # 棋盘状态
self.players = ['A', 'B'] # 玩家列表
self.scores = {'A': 0, 'B': 0} # 分数统计
self.current_player = self.players[0] # 当前玩家
self.game_over = False # 游戏是否结束标志
# 初始化棋盘状态
for i in range(n):
for j in range(n):
self.board[(i, j)] = {'H': False, 'V': False}
# 输出当前棋盘状态
def print_board(self):
for i in range(self.n):
# 打印水平线
for j in range(self.n):
if self.board[(i, j)]['H']:
print('---', end='')
else:
print(' ', end='')
if j == self.n-1:
print('')
# 打印竖直线
for j in range(self.n):
if self.board[(i, j)]['V']:
print('| ', end='')
else:
print(' ', end='')
if j == self.n-1:
print('')
# 检查当前位置是否可行
def check_move(self, pos, direction):
if direction == 'H' and (pos[0] < 0 or pos[0] >= self.n or pos[1] < 0 or pos[1] >= self.n-1):
return False
elif direction == 'V' and (pos[0] < 0 or pos[0] >= self.n-1 or pos[1] < 0 or pos[1] >= self.n):
return False
elif self.board[pos][direction]:
return False
else:
return True
# 下棋操作
def play(self, pos, direction):
if self.check_move(pos, direction):
self.board[pos][direction] = True
self.update_scores(pos, direction)
if self.check_game_over():
self.game_over = True
else:
self.current_player = self.players[(self.players.index(self.current_player)+1) % 2]
# 更新分数
def update_scores(self, pos, direction):
if direction == 'H':
if pos[0] > 0 and self.board[(pos[0]-1, pos[1])]['H'] and self.board[(pos[0]-1, pos[1])]['V'] and self.board[(pos[0]-1, pos[1]+1)]['V']:
self.scores[self.current_player] += 1
if pos[0] < self.n-1 and self.board[(pos[0]+1, pos[1])]['H'] and self.board[(pos[0], pos[1])]['V'] and self.board[(pos[0], pos[1]+1)]['V']:
self.scores[self.current_player] += 1
elif direction == 'V':
if pos[1] > 0 and self.board[(pos[0], pos[1]-1)]['V'] and self.board[(pos[0], pos[1]-1)]['H'] and self.board[(pos[0]+1, pos[1]-1)]['H']:
self.scores[self.current_player] += 1
if pos[1] < self.n-1 and self.board[(pos[0], pos[1]+1)]['V'] and self.board[(pos[0]+1, pos[1])]['H'] and self.board[(pos[0]+1, pos[1]+1)]['H']:
self.scores[self.current_player] += 1
# 检查游戏是否结束
def check_game_over(self):
for i in range(self.n):
for j in range(self.n):
if not self.board[(i, j)]['H'] or not self.board[(i, j)]['V']:
return False
return True
# 测试
game = DotsAndBoxes(3)
while not game.game_over:
game.print_board()
print('当前玩家:', game.current_player)
x = input('请输入横坐标:')
y = input('请输入纵坐标:')
d = input('请输入方向(H/V):')
game.play((int(x), int(y)), d)
print('游戏结束!')
print('玩家A得分:', game.scores['A'])
print('玩家B得分:', game.scores['B'])
```
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