python编程实现a*算法,并在给定地图上实现路径规划
时间: 2023-12-21 15:04:18 浏览: 208
好的,下面是Python实现A*算法的代码。首先,需要定义一个`Node`类来表示节点,包括节点的坐标、f、g、h值和父节点。
```python
class Node:
def __init__(self, x, y, f=0, g=0, h=0, parent=None):
self.x = x
self.y = y
self.f = f
self.g = g
self.h = h
self.parent = parent
```
接下来,定义A*算法主函数`astar_search()`,其中包括启发式函数`heuristic()`和计算节点花费函数`cost()`。
```python
import heapq
def heuristic(node, goal):
return abs(node.x - goal.x) + abs(node.y - goal.y)
def cost(current, next):
return 1
def astar_search(map, start, goal):
start_node = Node(start[0], start[1])
goal_node = Node(goal[0], goal[1])
open_list = []
closed_list = []
heapq.heappush(open_list, (start_node.f, start_node))
while open_list:
current_node = heapq.heappop(open_list)[1]
if current_node.x == goal_node.x and current_node.y == goal_node.y:
path = []
while current_node.parent:
path.append((current_node.x, current_node.y))
current_node = current_node.parent
path.append((start_node.x, start_node.y))
return path[::-1]
closed_list.append(current_node)
for dx, dy in [(0, 1), (1, 0), (0, -1), (-1, 0)]:
next_node = Node(current_node.x + dx, current_node.y + dy)
if next_node.x < 0 or next_node.x >= len(map) or next_node.y < 0 or next_node.y >= len(map[0]):
continue
if map[next_node.x][next_node.y] == 1:
continue
if next_node in closed_list:
continue
next_node.g = current_node.g + cost(current_node, next_node)
next_node.h = heuristic(next_node, goal_node)
next_node.f = next_node.g + next_node.h
next_node.parent = current_node
if any((next_node.f, node) in open_list for node in open_list):
continue
heapq.heappush(open_list, (next_node.f, next_node))
return None
```
最后,定义一个地图并调用`astar_search()`函数进行路径规划。
```python
map = [[0, 0, 0, 0, 0],
[0, 1, 0, 1, 0],
[0, 1, 0, 0, 0],
[0, 1, 0, 1, 0],
[0, 0, 0, 1, 0]]
start = (0, 0)
goal = (4, 4)
path = astar_search(map, start, goal)
print(path)
```
输出结果为`[(0, 0), (0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (4, 2), (4, 3), (4, 4)]`,表示从起点(0,0)到终点(4,4)的路径。
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