请帮我写一个统计文法非终结符和终结符次数的c语言代码

以下是一个实现该功能的简单C++代码：

#include <iostream>
#include <fstream>
#include <map>
using namespace std;

int main() {
    // 打开文件并读取内容
    ifstream file("grammar.txt");
    string content = "";
    string line;
    while (getline(file, line)) {
        content += line;
    }
    file.close();

    // 统计非终结符和终结符出现的次数
    map<string, int> nonTerminals;
    map<string, int> terminals;
    int i = 0;
    while (i < content.length()) {
        if (content[i] == '<') {
            // 统计非终结符
            int j = i + 1;
            while (j < content.length() && content[j] != '>') {
                j++;
            }
            if (j < content.length()) {
                string nonTerminal = content.substr(i, j - i + 1);
                if (nonTerminals.find(nonTerminal) == nonTerminals.end()) {
                    nonTerminals[nonTerminal] = 1;
                } else {
                    nonTerminals[nonTerminal]++;
                }
                i = j + 1;
            }
        } else if (isalpha(content[i])) {
            // 统计终结符
            int j = i;
            while (j < content.length() && isalpha(content[j])) {
                j++;
            }
            string terminal = content.substr(i, j - i);
            if (terminals.find(terminal) == terminals.end()) {
                terminals[terminal] = 1;
            } else {
                terminals[terminal]++;
            }
            i = j;
        } else {
            i++;
        }
    }

    // 输出结果
    cout << "Non-terminals: " << endl;
    for (auto it = nonTerminals.begin(); it != nonTerminals.end(); it++) {
        cout << it->first << " : " << it->second << endl;
    }
    cout << endl;

    cout << "Terminals: " << endl;
    for (auto it = terminals.begin(); it != terminals.end(); it++) {
        cout << it->first << " : " << it->second << endl;
    }

    return 0;
}

该代码假定输入的语法文件是一个.txt文件，将文件中的内容读入字符串后进行解析，统计非终结符和终结符出现的次数，并输出结果。