pygame跑酷小游戏代码，要求：1分钟内获得一千积分游戏通关否则游戏失败

下面是一个实现要求的pygame跑酷小游戏代码：

import pygame
import random

pygame.init()

# 游戏窗口大小
SCREEN_WIDTH = 800
SCREEN_HEIGHT = 600

# 颜色定义
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)
BLUE = (0, 0, 255)
GREEN = (0, 255, 0)
RED = (255, 0, 0)

# 创建游戏窗口
screen = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT))
pygame.display.set_caption('跑酷小游戏')

# 加载玩家图片
player_img = pygame.image.load('player.png')
player_width = 50
player_height = 50

# 加载障碍物图片
obstacle_img = pygame.image.load('obstacle.png')
obstacle_width = 50
obstacle_height = 50

# 加载背景图片
bg_img = pygame.image.load('bg.png')

# 设置字体
font = pygame.font.SysFont(None, 50)

# 定义玩家类
class Player(pygame.sprite.Sprite):
    def __init__(self):
        super().__init__()
        self.image = player_img
        self.rect = self.image.get_rect()
        self.rect.x = SCREEN_WIDTH // 2
        self.rect.y = SCREEN_HEIGHT - player_height - 10
        self.speed_x = 0
        self.speed_y = 0

    def update(self):
        # 移动玩家
        self.rect.x += self.speed_x
        self.rect.y += self.speed_y

        # 碰到边界停止移动
        if self.rect.x < 0:
            self.rect.x = 0
        elif self.rect.x > SCREEN_WIDTH - player_width:
            self.rect.x = SCREEN_WIDTH - player_width
        if self.rect.y < 0:
            self.rect.y = 0
        elif self.rect.y > SCREEN_HEIGHT - player_height:
            self.rect.y = SCREEN_HEIGHT - player_height

# 定义障碍物类
class Obstacle(pygame.sprite.Sprite):
    def __init__(self):
        super().__init__()
        self.image = obstacle_img
        self.rect = self.image.get_rect()
        self.rect.x = random.randint(0, SCREEN_WIDTH - obstacle_width)
        self.rect.y = -obstacle_height
        self.speed_y = random.randint(4, 10)

    def update(self):
        # 移动障碍物
        self.rect.y += self.speed_y

# 创建精灵组
all_sprites = pygame.sprite.Group()
obstacles = pygame.sprite.Group()

# 创建玩家和障碍物
player = Player()
all_sprites.add(player)

for i in range(10):
    obstacle = Obstacle()
    all_sprites.add(obstacle)
    obstacles.add(obstacle)

# 游戏主循环
game_over = False
score = 0
clock = pygame.time.Clock()

while not game_over:
    # 事件处理
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True
        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                player.speed_x = -5
            elif event.key == pygame.K_RIGHT:
                player.speed_x = 5
            elif event.key == pygame.K_UP:
                player.speed_y = -5
            elif event.key == pygame.K_DOWN:
                player.speed_y = 5
        elif event.type == pygame.KEYUP:
            if event.key == pygame.K_LEFT or event.key == pygame.K_RIGHT:
                player.speed_x = 0
            elif event.key == pygame.K_UP or event.key == pygame.K_DOWN:
                player.speed_y = 0

    # 更新精灵组
    all_sprites.update()

    # 绘制背景
    screen.blit(bg_img, (0, 0))

    # 绘制精灵组
    all_sprites.draw(screen)

    # 检测碰撞
    hits = pygame.sprite.spritecollide(player, obstacles, False)
    if hits:
        game_over = True

    # 绘制得分
    score += 1
    text = font.render('得分：{}'.format(score), True, WHITE)
    screen.blit(text, (10, 10))

    # 更新屏幕
    pygame.display.update()

    # 控制帧率
    clock.tick(60)

    # 判断游戏是否通关
    if score >= 1000:
        game_over = True

# 游戏结束，显示通关或失败信息
if score >= 1000:
    text = font.render('恭喜通关！', True, GREEN)
else:
    text = font.render('很遗憾，游戏失败！', True, RED)

screen.blit(text, (SCREEN_WIDTH // 2 - 150, SCREEN_HEIGHT // 2 - 25))
pygame.display.update()

while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()

该代码实现了玩家控制一个小人在随机生成的障碍物中跑酷，并计算得分，当玩家获得一千积分时游戏通关，否则游戏失败。你可以根据自己的需要修改代码并添加更多的游戏元素。