用pygame做一个扫雷游戏

好的，下面是一个使用Pygame制作的简单扫雷游戏示例：

import pygame
import random

# 初始化pygame
pygame.init()

# 设置游戏窗口的大小
screen_width = 400
screen_height = 400
screen = pygame.display.set_mode((screen_width, screen_height))

# 设置游戏标题
pygame.display.set_caption("扫雷游戏")

# 设置游戏背景颜色
background_color = (255, 255, 255)

# 设置游戏结束的标志
game_over = False

# 设置游戏时钟
clock = pygame.time.Clock()

# 定义方格的大小和数量
grid_size = 20
grid_count_x = screen_width // grid_size
grid_count_y = screen_height // grid_size

# 定义雷的数量
mine_count = 20

# 随机生成雷的位置
mines = []
for _ in range(mine_count):
    mine = [random.randint(0, grid_count_x - 1), random.randint(0, grid_count_y - 1)]
    if mine not in mines:
        mines.append(mine)

# 定义方格状态
grid_status = [[0] * grid_count_x for _ in range(grid_count_y)]  # 0代表未揭示，1代表揭示，2代表标记雷

# 游戏循环
while not game_over:
    # 处理游戏事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True
        elif event.type == pygame.MOUSEBUTTONDOWN:
            if event.button == 1:  # 左键点击
                mouse_pos = pygame.mouse.get_pos()
                grid_x = mouse_pos[0] // grid_size
                grid_y = mouse_pos[1] // grid_size
                if grid_status[grid_y][grid_x] == 0:
                    if [grid_x, grid_y] in mines:
                        # 点到雷，游戏结束
                        game_over = True
                    else:
                        # 统计周围雷的数量
                        count = 0
                        for dx in [-1, 0, 1]:
                            for dy in [-1, 0, 1]:
                                if dx == 0 and dy == 0:
                                    continue
                                nx = grid_x + dx
                                ny = grid_y + dy
                                if nx >= 0 and nx < grid_count_x and ny >= 0 and ny < grid_count_y:
                                    if [nx, ny] in mines:
                                        count += 1
                        grid_status[grid_y][grid_x] = count + 1
            elif event.button == 3:  # 右键点击
                mouse_pos = pygame.mouse.get_pos()
                grid_x = mouse_pos[0] // grid_size
                grid_y = mouse_pos[1] // grid_size
                if grid_status[grid_y][grid_x] == 0:
                    grid_status[grid_y][grid_x] = 2
                elif grid_status[grid_y][grid_x] == 2:
                    grid_status[grid_y][grid_x] = 0

    # 绘制游戏界面
    screen.fill(background_color)
    for y in range(grid_count_y):
        for x in range(grid_count_x):
            rect = pygame.Rect(x * grid_size, y * grid_size, grid_size, grid_size)
            pygame.draw.rect(screen, (192, 192, 192), rect)
            if grid_status[y][x] == 1:
                pygame.draw.rect(screen, (128, 128, 128), rect)
                if [x, y] in mines:
                    pygame.draw.circle(screen, (0, 0, 0), (x * grid_size + grid_size // 2, y * grid_size + grid_size // 2), grid_size // 4)
                else:
                    if grid_status[y][x] > 1:
                        font = pygame.font.SysFont(None, grid_size // 2)
                        text = font.render(str(grid_status[y][x] - 1), True, (0, 0, 0))
                        screen.blit(text, (x * grid_size + grid_size // 3, y * grid_size + grid_size // 3))
            elif grid_status[y][x] == 2:
                font = pygame.font.SysFont(None, grid_size // 2)
                text = font.render("雷", True, (255, 0, 0))
                screen.blit(text, (x * grid_size + grid_size // 3, y * grid_size + grid_size // 3))

    # 更新游戏显示
    pygame.display.update()

    # 控制游戏帧率
    clock.tick(30)

# 退出游戏
pygame.quit()

这个扫雷游戏使用方格来表示雷区，玩家可以通过左键点击方格来揭示方格，如果揭示到雷，游戏结束；如果揭示到的方格周围有雷，方格上方会显示雷的数量；玩家可以通过右键点击方格来标记可能的雷。游戏界面使用了灰色的方格表示未揭示的方格，揭示后的方格会变成浅灰色，雷会显示为黑色圆圈，标记雷的方格会显示红色的"雷"字样。