C语言扫雷游戏程序怎么写
时间: 2023-12-03 07:02:37 浏览: 40
关于C语言扫雷游戏程序的写法,需要对C语言的基本语法和游戏逻辑有一定的掌握。具体步骤包括:1.设计游戏地图和雷区;2.生成雷的位置和数量,并计算周围雷的数量;3.通过循环控制实现游戏的主逻辑,包括翻开格子、标记雷等操作;4.判断游戏结束的条件,包括翻开所有非雷格子、标记所有雷等。同时需要注意安全问题,如数组越界、内存泄露等。完整的程序可以通过参考相关的教程和代码进行实现。
相关问题
做一个c语言扫雷游戏代码
以下是一个简单的C语言扫雷游戏代码,仅供参考:
```c
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define ROW 9
#define COL 9
#define MINE 10
char board[ROW][COL];
char show[ROW][COL];
void init_board();
void set_mine();
void show_board();
void play_game();
void open(int row, int col);
int main()
{
init_board();
set_mine();
play_game();
return 0;
}
void init_board()
{
int i, j;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
board[i][j] = '0';
show[i][j] = '*';
}
}
}
void set_mine()
{
int i, j, count = 0;
srand((unsigned)time(NULL));
while (count < MINE) {
i = rand() % ROW;
j = rand() % COL;
if (board[i][j] != 'M') {
board[i][j] = 'M';
count++;
}
}
}
void show_board()
{
int i, j;
printf("\n ");
for (i = 0; i < COL; i++) {
printf("%d ", i + 1);
}
printf("\n");
for (i = 0; i < ROW; i++) {
printf("%d ", i + 1);
for (j = 0; j < COL; j++) {
printf("%c ", show[i][j]);
}
printf("\n");
}
}
void play_game()
{
int row, col, count = ROW * COL - MINE;
while (count > 0) {
show_board();
printf("Enter the row and column: ");
scanf("%d%d", &row, &col);
if (row < 1 || row > ROW || col < 1 || col > COL) {
printf("Invalid input!\n");
continue;
}
if (board[row - 1][col - 1] == 'M') {
printf("Game over!\n");
show_board();
return;
}
open(row - 1, col - 1);
count--;
}
printf("You win!\n");
show_board();
}
void open(int row, int col)
{
if (row < 0 || row >= ROW || col < 0 || col >= COL || show[row][col] != '*') {
return;
}
int i, j, count = 0;
for (i = row - 1; i <= row + 1; i++) {
for (j = col - 1; j <= col + 1; j++) {
if (i >= 0 && i < ROW && j >= 0 && j < COL && board[i][j] == 'M') {
count++;
}
}
}
if (count > 0) {
show[row][col] = count + '0';
} else {
show[row][col] = '/';
open(row - 1, col - 1);
open(row - 1, col);
open(row - 1, col + 1);
open(row, col - 1);
open(row, col + 1);
open(row + 1, col - 1);
open(row + 1, col);
open(row + 1, col + 1);
}
}
```
该代码使用二维数组实现了一个9x9的扫雷游戏,其中包含10个地雷。玩家先输入行和列的坐标,然后程序会根据玩家的输入判断是否命中地雷,如果命中则游戏结束,否则程序会根据玩家的输入进行递归展开周围的格子,直到所有非地雷的格子都被展开,或者命中地雷。最终如果所有非地雷的格子都被展开,则玩家获胜。
使用C语言写一个扫雷游戏
好的,以下是一个简单的C语言扫雷游戏的示例代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define ROWS 10
#define COLS 10
#define MINES 10
void print_board(char board[ROWS][COLS], int reveal_all);
int count_adjacent_mines(char board[ROWS][COLS], int row, int col);
void reveal_board(char board[ROWS][COLS], char revealed[ROWS][COLS], int row, int col);
int main() {
char board[ROWS][COLS];
char revealed[ROWS][COLS];
int i, j, row, col, mines_left = MINES, game_over = 0;
// Initialize board and revealed arrays to all ' '
for (i = 0; i < ROWS; i++) {
for (j = 0; j < COLS; j++) {
board[i][j] = ' ';
revealed[i][j] = ' ';
}
}
// Place mines randomly on the board
srand(time(NULL));
for (i = 0; i < MINES; i++) {
do {
row = rand() % ROWS;
col = rand() % COLS;
} while (board[row][col] == '*');
board[row][col] = '*';
}
printf("Welcome to Minesweeper!\n");
print_board(revealed, 0);
// Game loop
do {
printf("Mines left: %d\n", mines_left);
printf("Enter row and column (e.g. 1 2): ");
scanf("%d %d", &row, &col);
row--; // Convert to 0-based indexing
col--;
if (row < 0 || row >= ROWS || col < 0 || col >= COLS) {
printf("Invalid row or column.\n");
} else if (revealed[row][col] != ' ') {
printf("Already revealed.\n");
} else if (board[row][col] == '*') {
printf("Game over!\n");
game_over = 1;
reveal_board(board, revealed, row, col);
print_board(revealed, 1);
} else {
int adjacent_mines = count_adjacent_mines(board, row, col);
if (adjacent_mines > 0) {
revealed[row][col] = '0' + adjacent_mines;
} else {
reveal_board(board, revealed, row, col);
}
print_board(revealed, 0);
if (--mines_left == 0) {
printf("You win!\n");
game_over = 1;
}
}
} while (!game_over);
return 0;
}
// Print the game board
void print_board(char board[ROWS][COLS], int reveal_all) {
int i, j;
printf(" ");
for (j = 0; j < COLS; j++) {
printf("%d ", j + 1);
}
printf("\n");
for (i = 0; i < ROWS; i++) {
printf("%d ", i + 1);
for (j = 0; j < COLS; j++) {
if (board[i][j] == '*' && reveal_all) {
printf("* ");
} else {
printf("%c ", board[i][j]);
}
}
printf("\n");
}
}
// Count the number of adjacent mines
int count_adjacent_mines(char board[ROWS][COLS], int row, int col) {
int i, j, count = 0;
for (i = row - 1; i <= row + 1; i++) {
for (j = col - 1; j <= col + 1; j++) {
if (i >= 0 && i < ROWS && j >= 0 && j < COLS && board[i][j] == '*') {
count++;
}
}
}
return count;
}
// Recursively reveal the board
void reveal_board(char board[ROWS][COLS], char revealed[ROWS][COLS], int row, int col) {
if (row < 0 || row >= ROWS || col < 0 || col >= COLS || revealed[row][col] != ' ') {
return;
}
int adjacent_mines = count_adjacent_mines(board, row, col);
if (adjacent_mines > 0) {
revealed[row][col] = '0' + adjacent_mines;
} else {
revealed[row][col] = '-';
reveal_board(board, revealed, row - 1, col - 1);
reveal_board(board, revealed, row - 1, col);
reveal_board(board, revealed, row - 1, col + 1);
reveal_board(board, revealed, row, col - 1);
reveal_board(board, revealed, row, col + 1);
reveal_board(board, revealed, row + 1, col - 1);
reveal_board(board, revealed, row + 1, col);
reveal_board(board, revealed, row + 1, col + 1);
}
}
```
这个扫雷游戏是一个简单的控制台应用程序。它使用一个二维字符数组来表示游戏板,其中空格表示未揭示的方块,'*'表示地雷,数字表示相邻方块中的地雷数,'-'表示已揭示但没有地雷的方块。游戏使用递归算法来揭示相邻的方块,直到所有没有地雷的方块都被揭示出来为止。
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