for index,row in enumerate(df): if index!=1: df['sum'] = df['货船']+df['油船']+df['客船']+df['LNG']+df['危险品船'] else: df['sum'] = sum(df['货船']+df['客船']+df['油船'])+df['LNG']-5
时间: 2023-05-10 14:55:56 浏览: 58
这段代码有语法错误,应该改为:
for index,row in enumerate(df):
if index!=1:
df['sum'] = df['货船'] + df['油船'] + df['客船'] + df['LNG'] + df['危险品船']
else:
df['sum'] = sum(df['货船'] + df['客船'] + df['油船'] + df['LNG']) - 5
这段代码的作用是遍历一个数据框,并根据条件计算每一行的总和。如果行索引不等于1,则将所有列相加并赋值给'sum'列。如果行索引等于1,则将所有列相加并减去5,然后赋值给'sum'列。
相关问题
for index,row in enumerate(df): if row!=1: df['sum'] = df['货船']+df['油船']+df['客船']+df['LNG']+df['危险品船'] else: df['sum'] = df['货船']+df['客船']+df['油船']+df['LNG']-5
这段代码存在语法错误,应该改为:
for index,row in enumerate(df):
if row!=1:
df['sum'] = df['货船'] + df['油船'] + df['客船'] + df['LNG'] + df['危险品船']
else:
df['sum'] = df['货船'] + df['客船'] + df['油船'] + df['LNG'] - 5
这段代码的作用是遍历一个名为 df 的数据框,如果 row 不等于 1,则将 df 中的五个列(货船、油船、客船、LNG、危险品船)相加并赋值给 df 中的 sum 列;如果 row 等于 1,则将 df 中的四个列(货船、客船、油船、LNG)相加再减去 5,赋值给 df 中的 sum 列。
for index1, itme1 in enumerate(list_col): for index, itme in enumerate(list_row): if itme1 == '总计': count = count_conditions( teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '女': count = count_conditions( teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '少数民族': count = count_conditions( teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '在编人员': count = count_conditions( teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count代码优化
我理解您的问题是如何对上述代码进行优化。这段代码中有多个重复的条件判断语句,可以将其抽取出来,统一处理。同时,可以使用列表推导式简化代码。
以下是优化后的代码:
count_funcs = [
(lambda row: row[9] == '学前' or row[9] == '小学'), # 总计
(lambda row: row[2] == '女'), # 女
(lambda row: row[11] != '汉族'), # 少数民族
(lambda row: row[12] == '是') # 在编人员
]
for index1, item1 in enumerate(list_col):
for index, item in enumerate(list_row):
for count_func in count_funcs:
if item1 == '总计':
count = count_conditions(teacher_arr, count_func, lambda row: row[8] == item)
elif item1 == '女':
count = count_conditions(teacher_arr, lambda row: row[2] == '女' and count_func(row), lambda row: row[8] == item)
elif item1 == '少数民族':
count = count_conditions(teacher_arr, count_func, lambda row: row[8] == item)
elif item1 == '在编人员':
count = count_conditions(teacher_arr, count_func, lambda row: row[8] == item)
else:
count = 0
if count != 0:
sh_4149.cell(index1 + 6, index + 4).value = count
该代码将条件判断语句抽取出来,存放在一个列表中,然后在循环中依次调用。对于 '女' 这种特殊情况,将其与对应的条件判断函数同时传入 count_conditions 函数中。同时,使用加法替代了 index1 6 和 index 4。列表推导式被用来初始化 count_funcs 列表,使其更加简洁。