运行代码,进入调试模式,分析对象的构造函数和析构函数调用时机,代码如下: #include <iostream> using namespace std; class Base1 { protected: int data1; public: Base1(int a=8) { data1 = a; cout<<data1<<", Base1 Constructor\n"; } ~Base1( ) { cout<<data1<<", Base1 Destructor\n"; } }; class Base2 { protected: int data2; public: Base2(int a=9) { data2 = a; cout<<data2<<", Base2 Constructor\n"; } ~Base2( ) { cout<<data2<<", Base2 Destructor\n"; } }; class Derived:public Base1, public Base2 { int d; public: Derived(int x, int y, int z) : Base1(x), Base2(y) //A { d=z; cout<<"Derived Constructor\n"; } ~Derived( ) { cout<<"Derived Destructor\n"; } void Show( ) { cout<<data1<<','<<data2<<','<<d<<endl; } }; int main( ) { Derived c(1, 2, 3); c.Show( ); return 0; }先分析结果然后如果将A行代码替换为 Derived(int x,int y,int z),分析程序结果
时间: 2024-03-18 08:42:24 浏览: 25
深入解析C++中的构造函数和析构函数
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程序的输出结果是:
```
1, Base1 Constructor
2, Base2 Constructor
Derived Constructor
1,2,3
Derived Destructor
2, Base2 Destructor
1, Base1 Destructor
```
如果将A行代码替换为`Derived(int x,int y,int z)`,输出结果不会有变化,因为这是派生类的构造函数,会自动调用基类的构造函数。
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