c++实现输入整数集合{9 5 4 3 6 7}和{2 4 6 9 }，计算出它们进行集合的并、差和交运算后的结果，s1+s2 两个整数集合的并运算 s1-s2 两个整数集合的差运算 s1*s2 两个整数集合的交运算

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首先，我们可以使用C++中的STL容器set来表示整数集合。将题目中给出的两个集合分别存储在两个set中，代码如下：

#include <iostream>
#include <set>
using namespace std;

int main() {
    set<int> s1 = {9, 5, 4, 3, 6, 7};
    set<int> s2 = {2, 4, 6, 9};
    // 输出集合
    cout << "s1: ";
    for (auto it = s1.begin(); it != s1.end(); it++) {
        cout << *it << " ";
    }
    cout << endl;
    cout << "s2: ";
    for (auto it = s2.begin(); it != s2.end(); it++) {
        cout << *it << " ";
    }
    cout << endl;

    // 求并集
    set<int> s_union;
    set_union(s1.begin(), s1.end(), s2.begin(), s2.end(),
              inserter(s_union, s_union.begin()));
    cout << "s1 + s2: ";
    for (auto it = s_union.begin(); it != s_union.end(); it++) {
        cout << *it << " ";
    }
    cout << endl;

    // 求差集
    set<int> s_diff;
    set_difference(s1.begin(), s1.end(), s2.begin(), s2.end(),
                   inserter(s_diff, s_diff.begin()));
    cout << "s1 - s2: ";
    for (auto it = s_diff.begin(); it != s_diff.end(); it++) {
        cout << *it << " ";
    }
    cout << endl;

    // 求交集
    set<int> s_intersection;
    set_intersection(s1.begin(), s1.end(), s2.begin(), s2.end(),
                     inserter(s_intersection, s_intersection.begin()));
    cout << "s1 * s2: ";
    for (auto it = s_intersection.begin(); it != s_intersection.end(); it++) {
        cout << *it << " ";
    }
    cout << endl;

    return 0;
}

输出结果如下：

s1: 3 4 5 6 7 9 
s2: 2 4 6 9 
s1 + s2: 2 3 4 5 6 7 9 
s1 - s2: 3 5 7 
s1 * s2: 4 6 9 

以上代码通过使用STL库中的set容器，调用了set_union、set_difference和set_intersection函数，分别实现了并集、差集和交集的计算。