用java写一段代码验证:若√a >= √x >= √b,且√a,√b为相邻的正整数 则√x= (x-b) / (a-b) +√b
时间: 2024-05-31 18:07:25 浏览: 18
public class SqrtVerification {
public static void main(String[] args) {
int a = 4, b = 3, x = 3;
double sqrtA = Math.sqrt(a);
double sqrtB = Math.sqrt(b);
double sqrtX = Math.sqrt(x);
if (sqrtA >= sqrtX && sqrtX >= sqrtB && sqrtA - sqrtB == 1) {
double result = (x - b) / (double)(a - b) * sqrtB;
System.out.println("√x = " + sqrtX);
System.out.println("Result = " + result);
if (result == sqrtX) {
System.out.println("Verification passed.");
} else {
System.out.println("Verification failed.");
}
} else {
System.out.println("The conditions are not met.");
}
}
}
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