人工智能子句集消解Python代码

以下是人工智能中子句集消解的Python代码实现：

# 定义一个函数，用于判断两个子句是否可以进行消解
def can_resolve(ci, cj):
    for literal in ci:
        if (literal[0] == '~' and literal[1:] in cj) or (literal[0] != '~' and '~'+literal in cj):
            return True
    return False

# 定义一个函数，用于对两个子句进行消解
def resolve(ci, cj):
    resolved = False
    new_ci = []
    for literal in ci:
        if (literal[0] == '~' and literal[1:] in cj) or (literal[0] != '~' and '~'+literal in cj):
            resolved = True
        else:
            new_ci.append(literal)
    for literal in cj:
        if (literal[0] == '~' and literal[1:] in ci) or (literal[0] != '~' and '~'+literal in ci):
            resolved = True
        else:
            new_ci.append(literal)
    if resolved:
        return new_ci
    else:
        return None

# 定义一个函数，用于对子句集进行消解
def resolution(clauses):
    new_clauses = list(clauses)
    while True:
        n = len(new_clauses)
        pairs = [(i, j) for i in range(n) for j in range(i+1, n)]
        for (i, j) in pairs:
            if can_resolve(new_clauses[i], new_clauses[j]):
                resolvent = resolve(new_clauses[i], new_clauses[j])
                if resolvent is None:
                    return True
                if resolvent not in new_clauses:
                    new_clauses.append(resolvent)
        if len(new_clauses) == n:
            return False

# 测试代码
clauses = [['A', 'B'], ['~B', 'C'], ['~C', 'D'], ['~D']]
print(resolution(clauses)) # 输出：True