1.建立一个链表将实训12第2题定义的 学生数据存入链表，并读出显示出来。（10分） 数据为： { {"2020B200301","刘滨","男",18,{2020,9,20},70,85}, {"2020B200302","阚美娟","女",17,{2020,9,20},87,95}, {"2020B200303","胡大勇","男",17,{2020,9,20},69,80}, {"2020B200305","黎丽","女",18,{2020,9,20},68,88}, {"2020B200309","金鑫","男",19,{2019,9,1},90,85} }.{“2020B200303”,”胡大勇”,”男”,17,{2020,9,20},69,80}

好的，以下是代码实现：

#include <iostream>
#include <cstring>

using namespace std;

struct Student {
  char id[20]; // 学号
  char name[20]; // 姓名
  char gender[5]; // 性别
  int age; // 年龄
  int birthday[3]; // 生日，0-年，1-月，2-日
  int score1; // 第一科成绩
  int score2; // 第二科成绩
  Student *next; // 指向下一个节点的指针
};

void printStudent(Student *s) {
  cout << "学号：" << s->id << endl;
  cout << "姓名：" << s->name << endl;
  cout << "性别：" << s->gender << endl;
  cout << "年龄：" << s->age << endl;
  cout << "生日：" << s->birthday[0] << "-" << s->birthday[1] << "-" << s->birthday[2] << endl;
  cout << "第一科成绩：" << s->score1 << endl;
  cout << "第二科成绩：" << s->score2 << endl;
}

int main() {
  // 初始化数据
  Student s1 = {"2020B200301", "刘滨", "男", 18, {2020, 9, 20}, 70, 85, NULL};
  Student s2 = {"2020B200302", "阚美娟", "女", 17, {2020, 9, 20}, 87, 95, NULL};
  Student s3 = {"2020B200303", "胡大勇", "男", 17, {2020, 9, 20}, 69, 80, NULL};
  Student s4 = {"2020B200305", "黎丽", "女", 18, {2020, 9, 20}, 68, 88, NULL};
  Student s5 = {"2020B200309", "金鑫", "男", 19, {2019, 9, 1}, 90, 85, NULL};

  // 将节点串起来
  s1.next = &s2;
  s2.next = &s3;
  s3.next = &s4;
  s4.next = &s5;

  // 遍历链表并输出数据
  Student *p = &s1;
  while (p != NULL) {
    if (strcmp(p->id, "2020B200303") == 0) {
      // 找到了目标节点，输出数据并退出循环
      printStudent(p);
      break;
    }
    p = p->next;
  }

  return 0;
}

输出结果如下：

学号：2020B200303
姓名：胡大勇
性别：男
年龄：17
生日：2020-9-20
第一科成绩：69
第二科成绩：80