len() takes exactly one argument (2 given)

This error message means that the function len() was called with two arguments, but it expects only one argument.

For example, if you have the following code:

string1 = "hello"
string2 = "world"
length = len(string1, string2)

The len() function is being called with both string1 and string2 as arguments. However, len() only takes one argument, so the code will produce a TypeError with the message "len() takes exactly one argument (2 given)".

To fix this error, you need to call len() with only one argument, like this:

string1 = "hello"
length = len(string1)

相关问题

TypeError: len() takes exactly one argument (2 given)

This error message is indicating that the `len()` function was given two arguments, but it expected only one.

Here's an example of how this error might occur:

my_list = [1, 2, 3]
print(len(my_list, 2))

In this code, we're trying to call the `len()` function with two arguments: `my_list` and `2`. However, `len()` expects only one argument (the object whose length we want to find), so it raises a `TypeError`.

To fix this error, we need to pass only one argument to `len()`, like this:

my_list = [1, 2, 3]
print(len(my_list))

Now, `len()` is receiving only one argument (`my_list`), so it knows what to do and returns the correct length of the list (which is 3, in this case).

TypeError: len() takes exactly one argument (2 given)这啥错误

这个错误通常发生在调用 len() 函数时传递了多个参数的情况下。len() 函数只接受一个参数，该参数可以是一个序列、一个映射或一个集合，用于返回该序列、映射或集合中元素的数量。如果传递多个参数，会引发 TypeError 错误。

可能的原因是在调用 len() 函数时，将多个参数传递给它了，例如：

len(arg1, arg2)

应该将其修改为：

len(arg1)

或者需要将多个参数合并成一个序列、映射或集合，然后再将其传递给 len() 函数。