list.remove() takes exactly one argument (2 given)

This error message is raised when the `remove()` method of a list object is called with more or less than one argument.

For example:

my_list = [1, 2, 3, 4]
my_list.remove()  # Raises an error

In this example, `remove()` is called without any argument, which results in the error message because it requires one argument - the value to be removed.

On the other hand, if we pass more than one argument to `remove()`:

my_list = [1, 2, 3, 4]
my_list.remove(2, 3)  # Raises an error

In this example, `remove()` is called with two arguments - `2` and `3`, which results in the error message because it requires only one argument - the value to be removed.

相关问题

TypeError: set.remove() takes exactly one argument (0 given)

This error occurs when you try to call the `remove()` method on a set without passing any argument. The `remove()` method is used to remove a specific element from a set.

Here's an example of how to use the `remove()` method:

my_set = {1, 2, 3, 4}
my_set.remove(3)  # removes the element 3 from the set
print(my_set)  # prints {1, 2, 4}

If the element you're trying to remove is not in the set, you'll get a `KeyError`. To avoid this, you can use the `discard()` method instead, which doesn't raise an error if the element is not in the set:

my_set = {1, 2, 3, 4}
my_set.discard(5)  # doesn't raise an error, since 5 is not in the set
print(my_set)  # prints {1, 2, 3, 4}

list.append() takes exactly one argument (2 given)

这个错误消息的意思是，你在使用 `list.append()` 方法时给了它两个参数，但是这个方法只能接受一个参数。这意味着你应该只给 `list.append()` 方法传递一个参数。例如，如果你想向列表中添加一个新元素，你应该这样写：

my_list = [1, 2, 3]
my_list.append(4)  # correct

而不是这样：

my_list = [1, 2, 3]
my_list.append(4, 5)  # wrong - gives "TypeError: append() takes exactly one argument (2 given)"