请修改下面代码使它看起来不同,注意修改变量名和函数名并添加注释:library(gsl) n<-c(20,30,25,30,40,20,50,30,20,20) y<-c(6,1,1,0,5,4,1,8,4,7) p_alpha_beta<-function(alpha,beta,n,y){ a<-exp(alpha)/(1+exp(alpha))^2 b<-1 for(i in 1:length(n)){ x1<-exp(alpha)/(1+exp(-beta))+y[i] y1<-exp(alpha)/(1+exp(beta))+n[i]-y[i] x2<-exp(alpha)/(1+exp(-beta)) y2<-exp(alpha)/(1+exp(beta)) b<-bbeta(x1,y1)/beta(x2,y2) } result<-ab return(result) } estimate_lnk<-function(n,y){ alpha<-rt(length(n),df=4) beta<-rt(length(n),df=4) Num<-sum(alpha*p_alpha_beta(alpha,beta,n,y)/(dt(alpha,df=4)*dt(beta,df=4))) Den<-sum(p_alpha_beta(alpha,beta,n,y)/(dt(alpha,df=4)*dt(beta,df=4))) result<-Num/Den } result<-estimate_lnk(n,y)
时间: 2024-04-28 16:26:07 浏览: 8
# 修改后的代码如下:
library(gsl)
sample_size <- c(20,30,25,30,40,20,50,30,20,20)
success <- c(6,1,1,0,5,4,1,8,4,7)
# 定义函数 posterior_prob
posterior_prob <- function(alpha_val, beta_val, sample_size, success){
# 计算 p(y|alpha,beta) 中的 a 和 b
a <- exp(alpha_val)/(1+exp(alpha_val))^2
b <- 1
for(i in 1:length(sample_size)){
# 计算 x1, y1, x2, y2
x1 <- exp(alpha_val)/(1+exp(-beta_val))+success[i]
y1 <- exp(alpha_val)/(1+exp(beta_val))+sample_size[i]-success[i]
x2 <- exp(alpha_val)/(1+exp(-beta_val))
y2 <- exp(alpha_val)/(1+exp(beta_val))
# 计算 b 的值
b <- bbeta(x1,y1)/beta(x2,y2)
}
# 计算 p(alpha,beta|y)
result <- ab
return(result)
}
# 定义函数 lnk_estimate
lnk_estimate <- function(sample_size, success){
alpha_val <- rt(length(sample_size),df=4)
beta_val <- rt(length(sample_size),df=4)
Num <- sum(alpha_val*posterior_prob(alpha_val, beta_val, sample_size, success)/(dt(alpha_val,df=4)*dt(beta_val,df=4)))
Den <- sum(posterior_prob(alpha_val, beta_val, sample_size, success)/(dt(alpha_val,df=4)*dt(beta_val,df=4)))
result <- Num/Den
return(result)
}
# 调用函数 lnk_estimate 计算结果
result <- lnk_estimate(sample_size, success)