!RET&(!DFTRAMBYP&((TENA&! QNAPA&! CENA)|(!TENA&!TONAPA&!TCENA)) IDFTRAMBYP) &EMAA[2]&EMAA[1]&EMAA[O]&EMASA use the combination law and the distributive law to split all the bracket using perl
时间: 2024-01-31 19:03:40 浏览: 16
To split all the brackets using the combination law and the distributive law in Perl, you can use regular expressions and the substitution operator. Here's an example code snippet that should achieve what you're looking for:
```
#!/usr/bin/perl
use strict;
use warnings;
my $input = "!RET&(!DFTRAMBYP&((TENA&! QNAPA&! CENA)|(!TENA&!TONAPA&!TCENA)) IDFTRAMBYP) &EMAA[2]&EMAA[1]&EMAA[O]&EMASA";
# Apply the distributive law to split the innermost bracket
$input =~ s/(\([^()]+\))/$1/g while $input =~ /\([^()]+\)/;
# Apply the combination law to split remaining brackets
$input =~ s/\(([^()|&]+)([|&])([^()|&]+)\)/($1$2$input$2$3)/g while $input =~ /\([^()]+\)/;
print $input;
```
This code first applies the distributive law to split the innermost brackets, as in the previous example. Then it applies the combination law to split the remaining brackets.
The combination law states that `A&(B|C)` is equivalent to `(A&B)|(A&C)` and `A|(B&C)` is equivalent to `(A|B)&(A|C)`. The code uses these equivalences to split the brackets that contain `&` or `|` operators.
The regular expression `/\(([^()|&]+)([|&])([^()|&]+)\)/` matches any bracket that contains a `|` or `&` operator and captures the operands on either side of the operator. The substitution `($1$2$input$2$3)` replaces the bracket with two new brackets that apply the combination law.
Note that this code assumes that the input string is well-formed and does not contain any syntax errors.