Return the number of even ints in the given array. Note: the % "mod" operator computes the remainder, e.g. 5 % 2 is 1.

Sure, I can help you with that! Here's a Python code snippet that counts the number of even integers in an array:

def count_even_numbers(arr):
    count = 0
    for num in arr:
        if num % 2 == 0:
            count += 1
    return count

You can call this function with your array as an argument to get the number of even integers in the array. For example:

arr = [1, 2, 3, 4, 5, 6]
count = count_even_numbers(arr)
print(count)  # Output: 3

In this example, `count` will be equal to 3 because there are three even integers in the array (`2`, `4`, and `6`).