Return the number of even ints in the given array. Note: the % "mod" operator computes the remainder, e.g. 5 % 2 is 1.

Sure, I can help you with that! Here's a Python code snippet that counts the number of even integers in an array:

def count_even_numbers(arr):
    count = 0
    for num in arr:
        if num % 2 == 0:
            count += 1
    return count

You can call this function with your array as an argument to get the number of even integers in the array. For example:

arr = [1, 2, 3, 4, 5, 6]
count = count_even_numbers(arr)
print(count)  # Output: 3

In this example, `count` will be equal to 3 because there are three even integers in the array (`2`, `4`, and `6`).

相关问题

use java Return the number of even ints in the given array. Note: the % "mod" operator computes the remainder, e.g. 5 % 2 is 1. countEvens([2, 1, 2, 3, 4]) → 3 countEvens([2, 2, 0]) → 3 countEvens([1, 3, 5]) → 0

可以使用以下代码来实现：

public int countEvens(int[] nums) {
  int count = 0;
  for (int i = 0; i < nums.length; i++) {
    if (nums[i] % 2 == 0) {
      count++;
    }
  }
  return count;
}

该方法遍历整个数组，如果当前数字是偶数，则将计数器加1。最后返回计数器的值即为偶数个数。