判断A,B,C三个数大小，并将其从小到大代入x,y,z中，并且判断其中两个数是否能被3或7整除

你可以使用C++来实现这个功能。首先，你需要比较三个数A、B、C的大小并确定它们分别对应变量x、y、z。然后检查每个数是否能被3或7整除。以下是一个简单的示例代码：

#include <iostream>

bool isDivisible(int num, int divisor) {
    return num % divisor == 0;
}

int main() {
    int A, B, C;
    std::cout << "Enter three numbers (A, B, C): ";
    std::cin >> A >> B >> C;

    if (A <= B && A <= C) {
        x = A; // Assign the smallest number to x
        y = B;
        z = C;
    } else if (B <= A && B <= C) {
        x = B; // Assign the smallest number to x
        y = A;
        z = C;
    } else {
        x = C; // Assign the smallest number to x
        y = A;
        z = B;
    }

    bool divisibleBy3_x = isDivisible(x, 3);
    bool divisibleBy3_y = isDivisible(y, 3);
    bool divisibleBy3_z = isDivisible(z, 3);

    bool divisibleBy7_x = isDivisible(x, 7);
    bool divisibleBy7_y = isDivisible(y, 7);
    bool divisibleBy7_z = isDivisible(z, 7);

    std::cout << "Numbers ordered as x=" << x << ", y=" << y << ", z=" << z << "\n";
    std::cout << "x can be divided by 3: " << divisibleBy3_x << ", by 7: " << divisibleBy7_x << "\n";
    std::cout << "y can be divided by 3: " << divisibleBy3_y << ", by 7: " << divisibleBy7_y << "\n";
    std cout << "z can be divided by 3: " << divisibleBy3_z << ", by 7: " << divisibleBy7_z << "\n";

    return 0;
}

在这个代码中，`isDivisible` 函数用来检查一个数是否能被指定的数字整除。主函数里先获取三个数，然后根据条件排序，并检查每个排序后的数是否能被3或7整除。