int fun(int x){return (x==1)?1:(x+fun(x-1))}

The code you provided is a recursive function in C or C++ programming language.

The function is named "fun" and takes an integer argument "x". The function returns the sum of all integers from 1 to x, inclusive.

The function is implemented using recursion. If x is equal to 1, the function returns 1. Otherwise, the function recursively calls itself with the argument x-1, and adds x to the result of the recursive call. This continues until x is equal to 1, at which point the function returns 1 and the recursion stops.

However, there is a syntax error in the code. The function definition should end with a semicolon, like this:

int fun(int x){return (x==1)?1:(x+fun(x-1));}

相关问题

int fun(int x){return (x==1)?1:(x+fun(x-1))}; fun(2);

The code you provided defines a recursive function named "fun" that takes an integer argument "x" and returns the sum of all integers from 1 to x, inclusive. The function is implemented using recursion, and the function definition is correctly terminated with a semicolon.

The second part of the code `fun(2);` calls the "fun" function with an argument of 2, and expects to receive the result of the function call.

When the "fun" function is called with an argument of 2, the function recursively calls itself with an argument of 1, and then adds 2 to the result of the recursive call. The recursive call returns 1, because 1 is equal to 1. Therefore, the total sum returned by the function is 2 + 1 = 3.

So, the result of the function call `fun(2)` is 3.

单选颞 1分 int a=2: int fun(int k) { static int m=0; int n=0: ++m:++n:++k: return m+n+k+a: int main(void) printf("%ld\n", fun(a)): printf("%ld\n", fun(a+ +)); return O:

这段代码存在一些语法错误，我先修改一下：

#include <stdio.h>

int a = 2;

int fun(int k) {
    static int m = 0;
    int n = 0;
    ++m;
    ++n;
    ++k;
    return m + n + k + a;
}

int main(void) {
    printf("%d\n", fun(a));
    printf("%d\n", fun(a++));
    return 0;
}

这段代码的输出结果是：

8
12

第一个问题是什么？