能否提供一份简单的Java小游戏源代码示例，以便初学者理解？

当然可以。这里是一个简单的井字游戏（Tic Tac Toe）的Java源代码示例，它可以帮助初学者理解事件驱动编程和基本的游戏循环：

import java.util.Scanner;

public class TicTacToe {
    char[][] board = new char[3][3];
    char currentPlayer = 'X';

    void printBoard() {
        for (int i = 0; i < 3; i++) {
            for (char c : board[i]) {
                System.out.print(c + " ");
            }
            System.out.println();
        }
    }

    boolean placeMove(int row, int col) {
        if (board[row][col] != '\0') return false;
        board[row][col] = currentPlayer;
        currentPlayer = (currentPlayer == 'X') ? 'O' : 'X';
        return true;
    }

    public static void main(String[] args) {
        TicTacToe game = new TicTacToe();
        Scanner input = new Scanner(System.in);
        while (!game.isGameOver()) {
            game.printBoard();
            System.out.println("Enter your move (row column):");
            int row = input.nextInt() - 1;
            int col = input.nextInt() - 1;
            if (game.placeMove(row, col)) {
                if (game.checkWin()) {
                    System.out.println("Player " + currentPlayer + " wins!");
                    break;
                } else if (game.isBoardFull()) {
                    System.out.println("It's a tie!");
                    break;
                }
            }
        }
        input.close();
    }

    boolean isGameWon(char player) {
        // Check rows, columns, and diagonals for a win
        return ... // Implement the check conditions here
    }

    boolean isBoardFull() {
        for (char[] row : board) {
            for (char cell : row) {
                if (cell == '\0') return false;
            }
        }
        return true;
    }

    boolean isGameOver() {
        return isGameWon('X') || isGameWon('O') || isBoardFull();
    }
}

这个例子展示了创建一个棋盘、处理用户输入、检查游戏状态以及游戏结束条件的基本流程。你可以从这个简单的框架开始学习如何在Java中构建游戏。