帮我写一个扫雷的代码
时间: 2023-03-01 07:00:09 浏览: 83
扫雷程序代码
好的,我会写一个扫雷的代码给您。请注意,这仅是一个基本的代码实现,可以供您参考:
```python
class MineField:
def __init__(self, row, col, mines):
self.row = row
self.col = col
self.mines = mines
self.field = [[0] * col for _ in range(row)]
self.state = [[False] * col for _ in range(row)]
self.generate_mines()
self.calculate_mines()
def generate_mines(self):
mines = self.mines
while mines:
x = random.randint(0, self.row-1)
y = random.randint(0, self.col-1)
if self.field[x][y] == 0:
self.field[x][y] = -1
mines -= 1
def calculate_mines(self):
for i in range(self.row):
for j in range(self.col):
if self.field[i][j] == -1:
continue
count = 0
for x, y in [(i-1, j-1), (i-1, j), (i-1, j+1),
(i, j-1), (i, j+1),
(i+1, j-1), (i+1, j), (i+1, j+1)]:
if 0 <= x < self.row and 0 <= y < self.col and self.field[x][y] == -1:
count += 1
self.field[i][j] = count
def dfs(self, x, y):
if x < 0 or x >= self.row or y < 0 or y >= self.col:
return
if self.field[x][y] == -1 or self.state[x][y]:
return
self.state[x][y] = True
if self.field[x][y] == 0:
for i, j in [(x-1, y-1), (x-1, y), (x-1, y+1),
(x, y-1), (x, y+1),
(x+1, y-1), (x+1, y), (x+1, y+1)]:
self.dfs(i, j)
def show(self):
print('-' * (2 * self.col + 1))
for i in range(self.row):
line = '|'
for j in range(self.col):
if self.state[i][j]:
line += ' ' if self.field[i][j] == 0 else str(self.field[i][j])
else:
line += '*'
line += '|'
print(line)
print('-' * (2 * self.col + 1))
if __
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