俄罗斯方块python原码

以下是一个简单的俄罗斯方块游戏的 Python 原码：

import pygame
import random
 
# 初始化 Pygame
pygame.init()
 
# 游戏区域大小
size = (320, 480)
screen = pygame.display.set_mode(size)
 
# 游戏区域颜色
bg_color = (255, 255, 255)
 
# 游戏区域边界大小
border_size = 20
 
# 方块大小
block_size = 20
 
# 方块移动速度
block_speed = 1
 
# 方块下落速度
fall_speed = 1
 
# 方块颜色
colors = [
    (255, 0, 0),
    (0, 255, 0),
    (0, 0, 255),
    (255, 255, 0),
    (0, 255, 255),
    (255, 0, 255),
    (128, 128, 128),
]
 
# 方块类型
blocks = {
    0: [[1, 1, 1], [0, 1, 0]],
    1: [[1, 1, 0], [0, 1, 1]],
    2: [[0, 1, 1], [1, 1, 0]],
    3: [[1, 1], [1, 1]],
    4: [[1, 0, 0], [1, 1, 1]],
    5: [[0, 0, 1], [1, 1, 1]],
    6: [[1, 1, 1, 1]],
}
 
# 方块初始位置
block_x = 4
block_y = 0
 
# 随机生成方块
current_block = random.choice(list(blocks.keys()))
current_block_rotation = 0
current_block_color = random.choice(colors)
 
# 游戏区域数组
board = [[0 for x in range(10)] for y in range(20)]
 
# 循环更新游戏区域
done = False
while not done:
    # 监听事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            done = True
        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                # 左移方块
                if all(board[block_y + i][block_x - 1] == 0 for i, row in enumerate(blocks[current_block][current_block_rotation])):
                    block_x -= 1
            elif event.key == pygame.K_RIGHT:
                # 右移方块
                if all(board[block_y + i][block_x + len(blocks[current_block][current_block_rotation][0])] == 0 for i, row in enumerate(blocks[current_block][current_block_rotation])):
                    block_x += 1
            elif event.key == pygame.K_UP:
                # 旋转方块
                new_rotation = (current_block_rotation + 1) % len(blocks[current_block])
                if all(board[block_y + i][block_x + j] == 0 for i, row in enumerate(blocks[current_block][new_rotation]) for j, col in enumerate(row)):
                    current_block_rotation = new_rotation
            elif event.key == pygame.K_DOWN:
                # 快速下落方块
                while all(board[block_y + i + 1][block_x + j] == 0 for i, row in enumerate(blocks[current_block][current_block_rotation]) for j, col in enumerate(row)):
                    block_y += 1
 
    # 更新方块位置
    if fall_speed % 10 == 0:
        if all(board[block_y + i + 1][block_x + j] == 0 for i, row in enumerate(blocks[current_block][current_block_rotation]) for j, col in enumerate(row)):
            block_y += 1
        else:
            # 方块落地
            for i, row in enumerate(blocks[current_block][current_block_rotation]):
                for j, col in enumerate(row):
                    if col == 1:
                        board[block_y + i][block_x + j] = current_block_color
            # 生成新方块
            current_block = random.choice(list(blocks.keys()))
            current_block_rotation = 0
            current_block_color = random.choice(colors)
            block_x = 4
            block_y = 0
    fall_speed += 1
 
    # 绘制游戏区域
    screen.fill(bg_color)
    pygame.draw.rect(screen, (0, 0, 0), pygame.Rect(border_size, border_size, block_size * 10, block_size * 20), 1)
    for i, row in enumerate(board):
        for j, col in enumerate(row):
            if col != 0:
                pygame.draw.rect(screen, col, pygame.Rect(border_size + j * block_size, border_size + i * block_size, block_size, block_size))
    for i, row in enumerate(blocks[current_block][current_block_rotation]):
        for j, col in enumerate(row):
            if col == 1:
                pygame.draw.rect(screen, current_block_color, pygame.Rect(border_size + (block_x + j) * block_size, border_size + (block_y + i) * block_size, block_size, block_size))
 
    pygame.display.flip()
 
    # 控制游戏速度
    pygame.time.wait(50)
 
# 退出 Pygame
pygame.quit()

此代码是一个简单的实现，可以根据需要进行修改和扩展。