import random import matplotlib.pyplot as plt import numpy as np from matplotlib.font_manager import FontProperties X = [30, 60, 90, 120, 150, 180, 210] Y1 = [0.3, 0.5, 0.6, 0.7, 0.7, 0.8, 0.9] Y2 = [1.5, 11.3, 25.7, 58.3, 202.6, 345.2, 456.6] plt.plot(X, Y1, label='"Multiple cycles of exploration"') plt.plot(X, Y2, label='The optimal algorithm') plt.xlabel("The number of $t_{i}$") plt.ylabel("Running time/min") plt.legend() plt.show() 如何修改程序，使x轴只在30, 60, 90, 120, 150, 180, 210显示坐标？如何在折线图中相应的坐标上画点

要使x轴只显示指定的坐标，可以使用xticks函数来设置，如下所示：

import random 
import matplotlib.pyplot as plt 
import numpy as np 
from matplotlib.font_manager import FontProperties 

X = [30, 60, 90, 120, 150, 180, 210] 
Y1 = [0.3, 0.5, 0.6, 0.7, 0.7, 0.8, 0.9] 
Y2 = [1.5, 11.3, 25.7, 58.3, 202.6, 345.2, 456.6] 

plt.plot(X, Y1, label='"Multiple cycles of exploration"') 
plt.plot(X, Y2, label='The optimal algorithm') 
plt.xlabel("The number of $t_{i}$") 
plt.ylabel("Running time/min") 
plt.legend() 

plt.xticks(X)  # 设置x轴坐标为指定值

plt.show()

要在折线图中相应的坐标上画点，可以使用scatter函数来实现，如下所示：

import random 
import matplotlib.pyplot as plt 
import numpy as np 
from matplotlib.font_manager import FontProperties 

X = [30, 60, 90, 120, 150, 180, 210] 
Y1 = [0.3, 0.5, 0.6, 0.7, 0.7, 0.8, 0.9] 
Y2 = [1.5, 11.3, 25.7, 58.3, 202.6, 345.2, 456.6] 

plt.plot(X, Y1, label='"Multiple cycles of exploration"') 
plt.plot(X, Y2, label='The optimal algorithm') 
plt.xlabel("The number of $t_{i}$") 
plt.ylabel("Running time/min") 
plt.legend() 

plt.xticks(X)  # 设置x轴坐标为指定值

for i in range(len(X)):
    plt.scatter(X[i], Y1[i], color='blue')
    plt.scatter(X[i], Y2[i], color='orange')

plt.show()

这样就可以在相应的坐标上画点了。