请你用Java实现21点游戏
时间: 2024-09-22 17:04:40 浏览: 40
21点(也称为Blackjack)是一种流行的纸牌游戏,玩家的目标是尽量接近21点,但不超过它。下面是一个简单的Java实现基本版的21点游戏:
```java
import java.util.Scanner;
class Card {
int value;
String suit;
Card(int value, String suit) {
this.value = value;
this.suit = suit;
}
public int getValue() {
return value;
}
}
public class Blackjack {
private static final int JACK = 10, QUEEN = 10, KING = 10;
private int playerScore, dealerScore;
private Card[] deck;
public Blackjack() {
playerScore = 0;
dealerScore = 0;
deck = new Card[52];
for (int i = 0; i < 13; i++) {
for (int j = 0; j < 4; j++) {
deck[i * 4 + j] = new Card(i + 1, "Spades");
deck[i * 4 + j + 13] = new Card(i + 1, "Hearts");
deck[i * 4 + j + 26] = new Card(i + 1, "Diamonds");
deck[i * 4 + j + 39] = new Card(i + 1, "Clubs");
}
}
shuffleDeck();
}
// ... (更多方法,如洗牌、发牌、计算得分等)
private void dealCardToPlayer() {
if (playerScore + deck[deckIndex].getValue() <= 21) {
playerScore += deck[deckIndex].getValue();
} else {
playerScore++;
}
System.out.println("Your hand: " + playerScore);
}
private void playRound() {
while (true) {
dealCardToPlayer();
if (playerScore > 21) {
System.out.println("You bust! Dealer wins.");
break;
}
// ... (处理庄家行动,然后判断胜负)
}
}
public static void main(String[] args) {
Blackjack game = new Blackjack();
game.playRound();
}
// ... (其他辅助函数)
// Shuffle the deck to randomize cards
private void shuffleDeck() {
// ... (实现洗牌算法)
}
}
```
这个示例仅展示了游戏的基本框架,实际的完整版本会包括更多的细节,例如庄家始终得到一张明牌,除非超过21点,以及游戏是否结束的判断。注意,这只是一个简化的版本,用于教学目的,实际应用中需要考虑更多边缘情况和优化。
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