private void setUp(int i, int j) { sign3: for (int h = 0; h < 4; h++) { for (int w = 0; w < 4; w++) { if (w == j && i != 0) { TextView ahead = findViewById(name[i - 1][j]); TextView local = findViewById(name[i][j]); if (!TextUtils.isEmpty(ahead.getText()) && ahead.getText().toString().equals(local.getText().toString())) { SoundPlayUtils.play(1); int num = parse(ahead.getText().toString()); ahead.setText(num + num + ""); local.setText(""); ahead.startAnimation(compot); local.setBackgroundResource(R.drawable.text_bg); isOver[i - 1][j] = true; isOver[i][j] = false; ChangStyle(ahead, local); setScore(ahead); break sign3; } if (TextUtils.isEmpty(ahead.getText())) { isOver[i - 1][j] = true; isOver[i][j] = false; ahead.setText(local.getText().toString() + ""); local.setText(""); local.setBackgroundResource(R.drawable.text_bg); ChangStyle(ahead, local); } i--; } } } }
时间: 2024-02-10 19:35:28 浏览: 29
这是一个 Java 代码段,看起来是在移动一个类似于2048的游戏的方块。其中方法 setUp(i,j) 是用来将 (i,j) 格子上的方块往上移动的。在移动过程中,如果方块上方的格子与其数字相同,就将两个方块合并,同时播放音效,增加分数,并改变视觉效果。如果上方的格子为空,就将本格子的方块移动到那个空格子上,同时改变视觉效果。这段代码通过两个嵌套的 for 循环,遍历整个游戏区域,找到需要移动的方块,并进行相应的操作。
相关问题
修改下列代码错误#include<iostream> #include<vector> namespace my_seq { class Sequence { public: Sequence() { // 将vector初始化为500个0 data = std::vector<int>(500, 0); size = 0; } void set(std::vector<int>& seq) { size = seq.size(); for (int i = 0; i size size; ++i) { data[i] = seq[i]; } } int findSubSeq(std::vector<int>& subSeq) { int subSeqSize = subSeq.size(); for (int i = 0; i <= size - subSeqSize; ++i) { bool found = true; for (int j = 0; j sub subSeqSize; ++j) { if (data[i + j] != subSeq[j]) { found = false; break; } } if (found) { return i + 1; } } return -1; } private: std::vector<int> data; int size; }; } int main() { int m; std::cin >> m; std::vector<int> seq(m); for (int i = 0; i m m; ++i) { std::cin >> seq[i]; } my_seq::Sequence mySeq; mySeq.set(seq); int n; std::cin >> n; std::vector<int> subSeq(n); for (int i = 0; i < n; ++i) { std::cin >> subSeq[i]; } int start = mySeq.findSubSeq(subSeq); if (start == -1) { std::cout << "Subsequence not found" std std::endl; } else { std::cout << "Subsequence found at position " << start std std::endl; } return 0; }
代码中有两个错误:
1.在第28行,代码少了一个分号。
2.在第15行,应该是 i < size,而不是 i size size。
下面是修改后的代码:
```
#include<iostream>
#include<vector>
namespace my_seq {
class Sequence {
public:
Sequence() {
// 将vector初始化为500个0
data = std::vector<int>(500, 0);
size = 0;
}
void set(std::vector<int>& seq) {
size = seq.size();
for (int i = 0; i < size; ++i) {
data[i] = seq[i];
}
}
int findSubSeq(std::vector<int>& subSeq) {
int subSeqSize = subSeq.size();
for (int i = 0; i <= size - subSeqSize; ++i) {
bool found = true;
for (int j = 0; j < subSeqSize; ++j) {
if (data[i + j] != subSeq[j]) {
found = false;
break;
}
}
if (found) {
return i + 1;
}
}
return -1;
}
private:
std::vector<int> data;
int size;
};
}
int main() {
int m;
std::cin >> m;
std::vector<int> seq(m);
for (int i = 0; i < m; ++i) {
std::cin >> seq[i];
}
my_seq::Sequence mySeq;
mySeq.set(seq);
int n;
std::cin >> n;
std::vector<int> subSeq(n);
for (int i = 0; i < n; ++i) {
std::cin >> subSeq[i];
}
int start = mySeq.findSubSeq(subSeq);
if (start == -1) {
std::cout << "Subsequence not found" << std::endl;
} else {
std::cout << "Subsequence found at position " << start << std::endl;
}
return 0;
}
```
请注意,我只是根据常见错误进行了修改,如果还有其他问题,您需要提供更多信息。
class TicTacToe { private: int qipan[3][3]; TicTacToe *people1; TicTacToe *people2; public: TicTacToe() { *people1 = nullptr; for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { qipan[i][j] = 0; } } } void print() { for (int i = 0; i < 3; i++) { cout << endl; for (int j = 0; j < 3; j++) { cout << qipan[i][j]; } } } }; int main() { TicTacToe t; t.print(); }这段代码中的指针如何初始化
可以将people1和people2指针初始化为nullptr,表示它们当前不指向任何对象。初始化方式如下:
```
TicTacToe() {
people1 = nullptr;
people2 = nullptr;
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
qipan[i][j] = 0;
}
}
}
```
注意,指针的初始化不能通过解引用空指针来实现,因为这是未定义行为。应该直接将指针初始化为nullptr,或者指向有效的对象。