5.模拟“剪刀石头布”五局三胜猜拳游戏,选手和计算机轮流猜拳五次,三次胜利才算赢。算法分析:选手输入选项(“石头”“剪子”“布”),计算机随机给出选项,按照游戏规则——“布”>“石头”,“石头”>“剪刀”,“石头”>“布”进行评判和计数,一旦一方满足五局三胜,则游戏结束。
时间: 2024-10-23 15:16:05 浏览: 66
要模拟这个五局三胜的“剪刀石头布”游戏,可以按照以下步骤设计算法:
- 定义三个选项:玩家选择(player_choice)、计算机选择(computer_choice)以及判断输赢的规则(rule)。
choices = ["石头", "剪子", "布"]
rule = {"布": "石头", "石头": "剪子", "剪子": "布"}
- 初始化计分器:设置玩家和电脑的得分均为0。
player_score = 0
computer_score = 0
rounds_played = 0
max_rounds = 5
- 循环进行游戏,直到达到五局或某方赢得三局为止。
while rounds_played < max_rounds and player_score + computer_score != 3:
rounds_played += 1
# 玩家输入
player_choice = input("请输入你的选择(石头、剪子、布):")
# 计算机随机选择
computer_choice = random.choice(choices)
# 判断胜负并更新得分
if rule[player_choice] == computer_choice:
print(f"你出了{player_choice},电脑出了{computer_choice},平局!")
elif player_choice == rule[computer_choice]:
print(f"你出了{player_choice},电脑出了{computer_choice},你赢了!")
player_score += 1
else:
print(f"你出了{player_choice},电脑出了{computer_choice},你输了!")
computer_score += 1
print(f"当前比分:玩家{player_score} - {computer_score}")
# 游戏结束条件检查
if player_score >= 3:
print(f"恭喜你,玩家赢得了比赛!你总共玩了{rounds_played}轮。")
elif computer_score >= 3:
print(f"电脑赢了比赛!你总共玩了{rounds_played}轮。")
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