python 自动生成一个4:3大小适中复杂点的迷宫 迷宫起点到终点的路径用音符号标记出来

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为了生成一个4:3大小适中复杂点的迷宫，我们可以使用 Python 的 `random` 模块和 `numpy` 库来生成随机的迷宫。具体步骤如下：

1. 安装 `numpy` 库，可以使用以下命令进行安装：

   pip install numpy

2. 导入必要的库：

   import numpy as np
   import random

3. 设置迷宫的大小和墙壁的数量：

   width = 12  # 迷宫宽度
   height = 9  # 迷宫高度
   walls = int(width * height * 0.4)  # 墙壁数量

4. 生成一个随机的迷宫：

   maze = np.zeros((height, width), dtype=int)  # 创建一个空白迷宫

   # 随机生成墙壁
   for i in range(walls):
       x = random.randint(0, width - 1)
       y = random.randint(0, height - 1)
       maze[y][x] = 1

5. 为迷宫添加起点和终点：

   # 添加起点和终点
   start = (0, 0)
   end = (height - 1, width - 1)
   maze[start] = 0
   maze[end] = 0

6. 使用深度优先搜索或广度优先搜索算法找到起点到终点的路径，并用音符号标记出来。

   # 使用深度优先搜索算法找到起点到终点的路径
   def dfs(maze, start, end):
       stack = [start]
       visited = set()
       while stack:
           curr = stack.pop()
           if curr == end:
               return True
           visited.add(curr)
           for neighbor in get_neighbors(maze, curr):
               if neighbor not in visited:
                   stack.append(neighbor)
       return False

   # 获取当前位置的邻居节点
   def get_neighbors(maze, curr):
       row, col = curr
       neighbors = []
       if row > 0 and maze[row - 1][col] == 0:
           neighbors.append((row - 1, col))
       if row < maze.shape[0] - 1 and maze[row + 1][col] == 0:
           neighbors.append((row + 1, col))
       if col > 0 and maze[row][col - 1] == 0:
           neighbors.append((row, col - 1))
       if col < maze.shape[1] - 1 and maze[row][col + 1] == 0:
           neighbors.append((row, col + 1))
       return neighbors

   # 标记起点到终点的路径
   if dfs(maze, start, end):
       curr = start
       while curr != end:
           maze[curr] = 2
           for neighbor in get_neighbors(maze, curr):
               if maze[neighbor] == 2:
                   curr = neighbor
                   break

7. 最后，我们可以在终端输出迷宫，并将起点到终点的路径用音符号标记出来：

   # 输出迷宫
   for row in maze:
       for cell in row:
           if cell == 0:
               print(" ", end="")
           elif cell == 1:
               print("#", end="")
           elif cell == 2:
               print("*", end="")
       print()

   # 输出起点到终点的路径
   for row in maze:
       for cell in row:
           if cell == 0:
               print(" ", end="")
           elif cell == 1:
               print("#", end="")
           elif cell == 2:
               print("*", end="")
           elif cell == 3:
               print("do", end="")
           elif cell == 4:
               print("re", end="")
           elif cell == 5:
               print("mi", end="")
           elif cell == 6:
               print("fa", end="")
           elif cell == 7:
               print("so", end="")
           elif cell == 8:
               print("la", end="")
           elif cell == 9:
               print("ti", end="")
       print()

这样，我们就可以生成一个4:3大小适中复杂点的迷宫，并用音符号标记出起点到终点的路径了。