pop为100×36的矩阵,npop数值是100;function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1)+1; newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)]; end end end这个代码哪里错了,怎么修改
时间: 2023-06-11 08:08:50 浏览: 102
这个代码有几个错误:
1. 在定义变量 `c` 时,`1` 应该是 `+`,表示将 c 后面的部分连接在 i1 的前面,即 `c+1`。
2. 在交叉时,应该是 `i+1` 而非 `i 1`,即将第二个子代索引改为 `i+1`。
下面是修改后的代码:
```
function newPop = crossover(pop, nPop, pCross)
newPop = pop;
for i = 1:2:nPop
if rand < pCross
i1 = randi(nPop);
i2 = randi(nPop);
c = randi(size(pop,2)-1) + 1;
newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)];
newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)];
end
end
end
```
相关问题
pop为100×36的矩阵,npop数值是100,pCross数值是0.8;function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1)+1; newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)]; end end end 系统报错说newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)];的左侧索引与右侧的大小不兼容
这个错误是因为左侧的索引 `[i, :]` 所指定的大小与右侧的大小不兼容。具体来说,可能是由于 `pop(i1, 1:c)` 或 `pop(i2, c:end)` 的大小与 `pop(i, :)` 的大小不一致导致的。
你可以在运行代码时,打印出相应变量的大小,以便于调试。同时,你也可以尝试修改赋值语句,使得左右两侧的大小一致。
function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1); newPop(i,:) = [pop(i1,1:c), pop(i2,c+1:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c+1:end)]; end end end function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1)+1; newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)]; end end end有错误吗
是的,代码中有一个错误。在第10行和第12行中,变量c的赋值语句应该为:
```c = randi(size(pop,2)-1) + 1;```
这是因为我们需要将c设为一个介于1和size(pop,2)-1之间的随机整数,而randi函数返回的是介于1和size(pop,2)-1之间的随机整数,因此我们需要将其加1才能得到正确的结果。
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