编写10个线程，第一个线程从1加到10，第二个线程从11加20…第十个线程从91加到100，最后再把10个线程结果相加。java编写

好的，以下是Java代码实现：

public class MultiThreadAddition {
    private static final int THREAD_COUNT = 10;
    private static final int NUM_PER_THREAD = 10;

    public static void main(String[] args) throws InterruptedException {
        Thread[] threads = new Thread[THREAD_COUNT];
        AdditionThread[] additionThreads = new AdditionThread[THREAD_COUNT];

        // 创建并启动10个加法线程
        for (int i = 0; i < THREAD_COUNT; i++) {
            additionThreads[i] = new AdditionThread(i * NUM_PER_THREAD + 1, (i + 1) * NUM_PER_THREAD);
            threads[i] = new Thread(additionThreads[i]);
            threads[i].start();
        }

        // 等待10个加法线程全部执行结束
        for (int i = 0; i < THREAD_COUNT; i++) {
            threads[i].join();
        }

        // 计算10个加法线程的结果之和
        int sum = 0;
        for (int i = 0; i < THREAD_COUNT; i++) {
            sum += additionThreads[i].getResult();
        }

        System.out.println("1到100的和为：" + sum);
    }

    private static class AdditionThread implements Runnable {
        private final int startNum;
        private final int endNum;
        private int result;

        public AdditionThread(int startNum, int endNum) {
            this.startNum = startNum;
            this.endNum = endNum;
        }

        @Override
        public void run() {
            for (int i = startNum; i <= endNum; i++) {
                result += i;
            }
        }

        public int getResult() {
            return result;
        }
    }
}

运行结果：

1到100的和为：5050