python怎么求有十种元素的混淆矩阵，请举例说明结果

可以使用numpy库中的random模块生成一个10x10的随机矩阵，然后使用numpy库中的diag函数将对角线元素设置为0，即可得到一个有10种元素的混淆矩阵。

代码如下：

import numpy as np

# 生成10x10的随机矩阵
confusion_matrix = np.random.rand(10, 10)

# 将对角线元素设置为0
np.fill_diagonal(confusion_matrix, 0)

# 输出结果
print(confusion_matrix)

输出结果类似于：

array([[0.        , 0.16060167, 0.42345567, 0.12231492, 0.84656115,
        0.84310267, 0.4040992 , 0.41363432, 0.73379411, 0.62004253],
       [0.43862657, 0.        , 0.95682623, 0.06818387, 0.19970756,
        0.36575018, 0.24601277, 0.83441506, 0.42223819, 0.32047278],
       [0.88540612, 0.86176483, 0.        , 0.2548203 , 0.8013359 ,
        0.36159398, 0.71005589, 0.88655598, 0.26241485, 0.74371272],
       [0.39231016, 0.22342096, 0.66759412, 0.        , 0.80918635,
        0.75818706, 0.87357828, 0.77822371, 0.69232611, 0.03947092],
       [0.34833415, 0.35587127, 0.76451064, 0.45650828, 0.        ,
        0.70306768, 0.8780403 , 0.88206914, 0.84952314, 0.2693985 ],
       [0.37483668, 0.07187883, 0.51637816, 0.44472484, 0.10789073,
        0.        , 0.28746451, 0.87552048, 0.36927662, 0.0885662 ],
       [0.01734562, 0.68585448, 0.78611743, 0.79730363, 0.72875943,
        0.28789938, 0.        , 0.7432472 , 0.18777116, 0.00826618],
       [0.3227398 , 0.57627387, 0.93577123, 0.75226721, 0.58144427,
        0.5147646 , 0.8605439 , 0.        , 0.76484691, 0.7681058 ],
       [0.59616546, 0.4611425 , 0.68018123, 0.30335487, 0.4179826 ,
        0.5296206 , 0.43157516, 0.82233271, 0.        , 0.31094643],
       [0.75395744, 0.95056328, 0.37427338, 0.12683133, 0.19336816,
        0.76322801, 0.00932322, 0.79052333, 0.29247468, 0.        ]])