find_contours(dilated, contours, WIDTH, HEIGHT, 1000);这句C代码转换成verilog
时间: 2024-02-06 12:12:43 浏览: 136
CAN总线verilog代码
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将这句C代码转换为Verilog代码需要将其拆分成多个步骤,并使用Verilog语言实现。
以下是可能的Verilog实现步骤:
1. 在Verilog中定义输入和输出参数:
```verilog
module find_contours (
input [WIDTH*HEIGHT-1:0] dilated,
output [WIDTH*HEIGHT-1:0] contours
);
```
2. 在Verilog中实现初始化标记数组:
```verilog
reg [7:0] visited [0:HEIGHT-1][0:WIDTH-1];
integer i, j;
initial begin
for (i = 0; i < HEIGHT; i = i + 1) begin
for (j = 0; j < WIDTH; j = j + 1) begin
visited[i][j] = 0;
end
end
end
```
3. 在Verilog中实现寻找轮廓:
```verilog
integer label, area, queue_front, queue_rear, k;
reg [7:0] visited_tmp, in_tmp, out_tmp;
reg [15:0] queue_x [0:WIDTH*HEIGHT-1], queue_y [0:WIDTH*HEIGHT-1];
integer x, y;
initial begin
// 初始化标记数组
label = 1;
for (i = 1; i < HEIGHT - 1; i = i + 1) begin
for (j = 1; j < WIDTH - 1; j = j + 1) begin
visited_tmp = visited[i][j];
in_tmp = dilated[i*WIDTH+j];
if (in_tmp > 0 && visited_tmp == 0) begin
visited[i][j] = label;
area = 1;
queue_front = 0;
queue_rear = 0;
queue_x[queue_rear] = i;
queue_y[queue_rear] = j;
queue_rear = queue_rear + 1;
while (queue_front < queue_rear) begin
x = queue_x[queue_front];
y = queue_y[queue_front];
queue_front = queue_front + 1;
visited_tmp = visited[x-1][y];
in_tmp = dilated[(x-1)*WIDTH+y];
if (in_tmp > 0 && visited_tmp == 0) begin
visited[x-1][y] = label;
area = area + 1;
queue_x[queue_rear] = x - 1;
queue_y[queue_rear] = y;
queue_rear = queue_rear + 1;
end
visited_tmp = visited[x+1][y];
in_tmp = dilated[(x+1)*WIDTH+y];
if (in_tmp > 0 && visited_tmp == 0) begin
visited[x+1][y] = label;
area = area + 1;
queue_x[queue_rear] = x + 1;
queue_y[queue_rear] = y;
queue_rear = queue_rear + 1;
end
visited_tmp = visited[x][y-1];
in_tmp = dilated[x*WIDTH+y-1];
if (in_tmp > 0 && visited_tmp == 0) begin
visited[x][y-1] = label;
area = area + 1;
queue_x[queue_rear] = x;
queue_y[queue_rear] = y - 1;
queue_rear = queue_rear + 1;
end
visited_tmp = visited[x][y+1];
in_tmp = dilated[x*WIDTH+y+1];
if (in_tmp > 0 && visited_tmp == 0) begin
visited[x][y+1]
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