c语言2048游戏代码
时间: 2023-08-06 16:06:02 浏览: 57
下面是一个简单的 C 语言实现的 2048 游戏代码,仅供参考:
```c
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define ROW 4
#define COL 4
void init(int board[][COL])
{
int i, j;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
board[i][j] = 0;
}
}
}
void output(int board[][COL])
{
int i, j;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
printf("%4d", board[i][j]);
}
printf("\n");
}
}
void add_number(int board[][COL])
{
int i, j;
int empty_count = 0;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
if (board[i][j] == 0) {
empty_count++;
}
}
}
if (empty_count == 0) {
return;
}
int pos = rand() % empty_count;
int count = 0;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
if (board[i][j] == 0) {
if (count == pos) {
board[i][j] = rand() % 2 ? 2 : 4;
return;
}
count++;
}
}
}
}
void move_left(int board[][COL])
{
int i, j, k;
for (i = 0; i < ROW; i++) {
for (j = 0; j < COL; j++) {
for (k = j + 1; k < COL; k++) {
if (board[i][j] == 0 && board[i][k] != 0) {
board[i][j] = board[i][k];
board[i][k] = 0;
break;
} else if (board[i][j] != 0 && board[i][j] == board[i][k]) {
board[i][j] *= 2;
board[i][k] = 0;
break;
} else if (board[i][j] != 0 && board[i][k] != 0) {
break;
}
}
}
}
}
int main()
{
int board[ROW][COL];
srand(time(NULL));
init(board);
add_number(board);
add_number(board);
output(board);
char c;
while (scanf("%c", &c) != EOF) {
switch (c) {
case 'a':
move_left(board);
break;
case 'd':
// move_right(board);
break;
case 'w':
// move_up(board);
break;
case 's':
// move_down(board);
break;
default:
break;
}
add_number(board);
output(board);
}
return 0;
}
```
该代码实现了 2048 游戏的基本功能,包括初始化、输出、添加数字、向左移动等功能,但是其他方向的移动尚未实现,你可以自行尝试实现。